vector<vector<int>> kSmallestPairs(vector<int>& nums1, vector<int>& nums2,intk) { vector<vector<int>>res;for(inti =0; i < min((int)nums1.size(), k); ++i) {for(intj =0; j < min((int)nums2.size(), k); ++j) { res.
vector<vector<int>> kSmallestPairs(vector<int>& nums1, vector<int>& nums2,intk) { map<int, multiset<pair<int,int> > >pairSum;//遍历所有可能的数对,保存数对以及它们的和for(intj =0; j < nums2.size(); ++j) {for(inti =0; i < nums1.size(); ++i) { pairSum[nums1[i]+nums2...
Given a n x n matrix where each of the rows and columns are sorted in ascending order, find the kth smallest element in the matrix.Note that it is the kth smallest element in the sorted order, not the kth distinct element.Example:...
395. Longest Substring with At Least K Repeating Characters 给定小写字符串S和整数K,在S中寻找子串,该子串中所有字母出现的次数都大于等于K,求这样的子串的最长长度。 396. Rotate Function 给定长度为N的数组,它有N个旋转数组,用0~N-1对应乘以旋转数组,求最大值。 397. Integer Replacement 给定一个正整数...
373.Find-K-Pairs-with-Smallest-Sums (H) 668.Kth-Smallest-Number-in-Multiplication-Table (H-) 719.Find-Kth-Smallest-Pair-Distance (H-) 1918.Kth-Smallest-Subarray-Sum (M+) 2040.Kth-Smallest-Product-of-Two-Sorted-Arrays (H-) 1439.Find-the-Kth-Smallest-Sum-of-a-Matrix-With-Sorted-Rows...
0373 Find K Pairs with Smallest Sums Go 38.4% Medium 0374 Guess Number Higher or Lower Go 50.4% Easy 0375 Guess Number Higher or Lower II 46.3% Medium 0376 Wiggle Subsequence Go 48.2% Medium 0377 Combination Sum IV Go 52.1% Medium 0378 Kth Smallest Element in a Sorted Matrix Go ...
采用priority queue 或者 说在python 中的heapq 求top k 采用最小堆(默认) 采用最大堆的时候可以采用push 负的value 215. Kth Largest Element in an Array 347. Top K Frequent Elements 373. Find K Pairs with Smallest Sums 13. K路归并 K路归并能帮咱们解决那些涉及到多组排好序的数组的问题。 每当...
findMedian() -> 1.5 addNum(3) findMedian() -> 2 用一个最大堆存放比中位数小(或等于)的元素,用一个最小堆存放比中位数大(或等于)的元素。这里关键的方法是insert(),每当要插入一个元素时,根据判断条件将它插入最大堆或是最小堆,并更新最大堆和最小堆,使得最大堆和最小堆中元素的个数之差不超...
/ 2.0; } private: static int find_kth(int A[], int m, int B[], int n, int k...
时间O(nlongk) - treeset的底层是红黑树实现的 空间O(k) - 最多只放了K个元素 Java实现 1classSolution {2publicbooleancontainsNearbyAlmostDuplicate(int[] nums,intk,intt) {3//corner case4if(nums ==null|| nums.length < 2 || k == 0) {5returnfalse;6}78//normal case9TreeSet<Long> set...