53. Maximum Subarray Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array[-2,1,-3,4,-1,2,1,-5,4], the contiguous subarray[4,-1,2,1]has the largest sum =6. 题目地址:https://leetcode.com/problems/...
给你两个按非递减顺序排列的整数数组nums1和nums2,另有两个整数m和n,分别表示nums1和nums2中的元素数目。 请你合并nums2到nums1中,使合并后的数组同样按非递减顺序排列。 注意:最终,合并后数组不应由函数返回,而是存储在数组nums1中。为了应对这种情况,nums1的初始长度为m + n,其中前m个元素表示应合并的元...
4.when encounter hard problems, first thing you should do is cfindlassify which kind of problems it is. Classfy is very important for you to think solution. array/list/map/set/binary search/sort/bfs/dfs/union find/trie/suffix trie/dp/fenwick tree/heap/tree *find the duplicate number whe...
Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input array nums = [1,...
代码展示classSolution{publicint[]recoverArray(int[]nums){Arrays.sort(nums);Map<Integer,Integer>...
数组Array 在平时使用最多的恐怕就是数组了吧,它是使用最广泛的一种数据结构,它是相同数据类型(可以是基本类型也可以是自定义类型)的元素按一定顺序排列的集合,它们在内存中按照这个先后顺序连续存放在一起。有一维数组,二维数组,多维数组。通俗的理解就是我们一般把一群羊或者一群牛放在一个圈里面,这个圈就相当于...
459 Repeated Substring Pattern 39.7% Easy 460 LFU Cache 28.6% Hard Partition Equal Subset Sum 【题目】Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Each ...
【leetcode_easy_array】1295. Find Numbers with Even Number of Digits,problem1295. FindNumberswithEvenNumberofDigitssolution1:计算数据的位数;code:solution2:根据数据范围确定数据位数;code:参考1.leetcode_1295. FindNumberswith
Leetcode-Easy 977. Squares of a Sorted Array 题目描述 给定一个从小到大排序的整数数组A,然后将每个整数的平方和从小到大排序。 Example 1: Input: [-4,-1,0,3,10] Output: [0,1,9,16,100] Example 2: Input: [-7,-3,2,3,11] Output: [4,9,9,49,121]...
其他思路 假设有两个指针,分别从头和从尾向中间移动,然后比较左右两个值的绝对值大小,绝对值大的将平方和添加到最左边,一直到两个指针相遇。 class Solution:def sortedSquares(self, A):answer = [0] * len(A)l, r = 0, len(A) - 1while l <= r:left, right = abs(A[l]), abs(A[r])if ...