The diameter of an N-ary tree is the length of the longest path between any two nodes in the tree. This path may or may not pass through the root. (Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value.) Exam...
Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longestpath between any two nodes in a tree. This path may or may not pass through the root. Example: Given a binary tree 1 / \ 2 3 / \ 4 5 ...
543. Diameter of Binary Tree 描述: 求二叉树最长路径长度 思路: 深度优先搜索 代码 # Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: def diameterOfBinaryTree(self, root): """ ...
leetcode-543-Diameter of Binary Tree int dfs(root): the max. length of one of substree. i.e. dfs(root): if(root == null) return 0 left += dfs(root->left) right += dfs(root->right) res = max(res, left + right + 1); return max(left, right) + 1; 1. 2. 3. 4. 5....
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Can you solve this real interview question? Diameter of Binary Tree - Given the root of a binary tree, return the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This p
力扣leetcode-cn.com/problems/diameter-of-binary-tree/ 题目描述 给定一棵二叉树,你需要计算它的直径长度。一棵二叉树的直径长度是任意两个结点路径长度中的最大值。这条路径可能穿过也可能不穿过根结点。 示例: 给定二叉树 1 / \ 2 3 / \ 4 5 返回3, 它的长度是路径 [4,2,1,3] 或者 [5...
classSolution{intdiameter=;publicintdiameterOfBinaryTree(TreeNode root){ depth(root);return diameter;}publicintdepth(TreeNode node){if(node ==null)return;intleftLen= depth(node.left);// node左子树最大深度intrightLen= depth(node.right);// node右子树最大深度 diameter =Math.max(diameter...
543. Diameter of Binary Tree(二叉树的最长直径) 给定二叉树,您需要计算树直径的长度。二叉树的直径是一棵树中任何两个节点之间的最长路径的长度。此路径可能会也可能不会通过根。 思路: 要计算二叉树的最长直径,肯定需要遍历树,而最长直径肯定有一个相对的root节点,所以可以后序遍历了,每到达一个节点就要计算...
class Solution { private int max = 0; public int diameterOfBinaryTree(TreeNode root) { maxDepth(root); return max; } private int maxDepth(TreeNode root){ if(root == null) return 0; int l = maxDepth(root.left); int r = maxDepth(root.right); max = Math....