Dectect cycle in directed graph: Detect cycle in a directed graph is using aDFS. Depth First Traversal can be used to detect cycle in a Graph. DFS for a connected graph produces a tree. There is a cycle in a graph only if there is aback edgepresent in the graph. A back edge is an...
int[][] edges = {{0, 1}, {1, 2}, {2, 0}}; boolean result = so.hasCycleDirectedGraph(3, edges); System.out.println(result); } } Detect Cycle in Undirected Graph 无向图找环 Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of n...
2. Also, you could not based on it to detect a cycle. The above method only worksforDirected Graph. Analysis: ActuallyforUndireted Grpah, we have a classic algorithm to testifthere is a circle in the graph. And how many independent sets are there in a graph. The classic method is c...
1559.Detect-Cycles-in-2D-Grid (M) 1568.Minimum-Number-of-Days-to-Disconnect-Island (H-) 1617.Count-Subtrees-With-Max-Distance-Between-Cities (H-) 1654.Minimum-Jumps-to-Reach-Home (H-) 1905.Count-Sub-Islands (M+) 2045.Second-Minimum-Time-to-Reach-Destination (M+) 2101.Detonate-the-...
524 Longest Word in Dictionary through Deleting 40.20% Medium 523 Continuous Subarray Sum 21.30% Medium 522 Longest Uncommon Subsequence II 28.10% Medium 521 Longest Uncommon Subsequence I 50.70% Easy 520 Detect Capital 54.20% Easy 519 Random Flip Matrix 32.20% Medium 518 Coin Change 2 33.20% Medi...
LeetCode 刷题随手记 - 第一部分 前 256 题(非会员),仅算法题,的吐槽 https://leetcode.com/problemset/algorithms/...
maskLen = {reduce(lambda x, y: x | y, [1 << (ord(c) - 97) for c in word], 0): len(word) for word in sorted(words, key = lambda x: len(x))}.items() return max([x[1] * y[1] for i, x in enumerate(maskLen) for y in maskLen[:i] if not (x[0] & y[0])...
520 Detect Capital // #520 检查大写 描述:如题。 //#520Description: Detect Capital | LeetCode OJ 解法1:水题。 // Solution 1: Trivial. 代码1 //Code 1 521 Longest Uncommon Subsequence I // #521 最长不常见子序列1 描述:懒得解释。
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofeverynode never differ by more than 1. 【解答】checkBalanced方法用来递归检查是否平衡的,返回树高度,偷了个巧,如果发现不平衡抛出TreeUnbalancedException异常: ...
public ListNode detectCycle(ListNode head) { if (head == null) { return null; } ListNode slow = head; ListNode fast = head.next; boolean meet = false; int len = 0; // 判断是否有环,并计数 while (fast != null) { if (fast.next == null || fast.next.next == null) { ...