Thisproblem came in today'sLeetcode Weekly contest 296. The solution to this problem is pretty straightforward. But my question is: how can I solve the problem if the condition:operations[i][1] does not exist in numsis not necessarily true. As an example Input: nums = [1,2,3,4], ...
https://leetcode.cn/contest/cnunionpay2022/problems/6olJmJ/ 题意 贪心算法双指针 思路 本质为贪心算法,运动员的能力值尽可能的匹配大于等于他的能力值的训练师,因此我们对于能力值的运动员应当尽可能的匹配能力值低的训练师,这样我们才能保证最优匹配数量。 将运动员和训练师都按照能力的大小进行排序,每个运动...
代码如下: fromdatetimeimportdatetimeclassSolution:defdaysBetweenDates(self,date1:str,date2:str)->int:defisLeap(y):returny%4==0and(y%100!=0ory%400==0)deftoDays(date):y,m,d=map(int,date.split("-"))ans=(y-1971)*365+sum([isLeap(x)forxinrange(1971,y)])mdays=[0,31,29ifisLeap(y...
Today, Leet weekly contest was hold on time. However, i was late about 15 minutes for checking out of the hotel. It seems like every thing gone well. First problem was accepted by my first try. Second problem is not a complex task but has many coding work to solve it. What makes me...
摘要:Today, Leet weekly contest was hold on time. However, i was late about 15 minutes for checking out of the hotel. It seems like every thing gone well. 阅读全文 posted @ 2016-12-11 14:09 暴力的轮胎 阅读(365) 评论(0) 推荐(0) 【LeetCode】467. Unique Substrings in Wraparound...
After the contest, I continued improving my code, and eventually, I implemented aO(N2)algorithm, when I submitted the code again, but unfortunately again, I received same judging result with previousO(N∗N∗logN)one - "all cases are passed, but the result is TLE". ...
https://leetcode-cn.com/contest/weekly-contest-237/problems/check-if-...题解:判断句子是否为全字母句 一、题目大意 全字母句 指包含英语字母表中每个字母至少一次的句子。 给你一个仅由小写英文字母组成的字符串 sentence ,请你判断 sentence 是否为 全字母句 。 如果是,返回 true ;否则,返回 false ...
✅ Solutions to LeetCode by Go, 100% test coverage, runtime beats 100% / LeetCode 题解 books.halfrost.com/leetcode MIT License 0 stars 1.1k forks Star Watch Code Pull requests Actions Projects Security Insights master 5 branches 2 tags Go to file Code Clone HTTPS GitHub ...
输入: "Let's take LeetCode contest"输出: "s'teL ekat edoCteeL tsetnoc"注意:在字符串中,每个单词由单个空格分隔,并且字符串中不会有任何额外的空格。实现: public String reverseWords(String s) { if (s==null||s.length()==0){ return ""; } //在字符串中,每个单词由单个空格分隔,并且字...
(the important thing here is that the domains of these addresses are bmail.com). The next example illustrates the use of character '+' in email address aliases: addresses polycarp+contest@BMAIL.COM, Polycarp@bmail.com and polycarp++acm+icpc@Bmail.Com also correspond to the same account on ...