Ceiling of a Number (medium) Next Letter (medium) Number Range (medium) Search in a Sorted Infinite Array (medium) Minimum Difference Element (medium) Bitonic Array Maximum (easy) 12. Pattern: Top ‘K’ Elements,前K个系列 任何让我们求解最大/最小/最频繁的K个元素的题,都遵循这种模式。 用来...
Ceiling of a Number (medium) Next Letter (medium) Number Range (medium) Search in a Sorted Infinite Array (medium) Minimum Difference Element (medium) Bitonic Array Maximum (easy) 12. Pattern: Top ‘K’ Elements,前K个系列 经典题目: Top ‘K’ Numbers (easy) Kth Smallest Number (easy) ‘...
Ceiling of a Number (medium) Next Letter (medium) Number Range (medium) Search in a Sorted Infinite Array (medium) Minimum Difference Element (medium) Bitonic Array Maximum (easy) 12. Pattern: Top ‘K’ Elements,前K个系列 任何让我们求解最大/最小/最频繁的K个元素的题,都遵循这种模式。 用来...
Ceiling of a Number (medium) Next Letter (medium) Number Range (medium) Search in a Sorted Infinite Array (medium) Minimum Difference Element (medium) Bitonic Array Maximum (easy) 12. Pattern: Top ‘K’ Elements,前K个系列 经典题目: Top ‘K’ Numbers (easy) Kth Smallest Number (easy) ‘...
.. Ceiling of a Number (medium) .. Next Letter (medium) .. Number Range (medium) .. Search in a Sorted Infinite Array (medium) .. Minimum Difference Element (medium) .. Bitonic Array Maximum (easy) .. Problem Challenge 1: Search Bitonic Array (medium) .. Problem Challenge 2: Search...
= null && val <= t + set.floor(val)) return true; if (set.ceiling(val) != null && set.ceiling(val) <= t + val) return true; set.add(val); if (i >= k) set.remove(nums[i - k]); } return false; } } Contains Duplicate II 【题目】Given an array of integers and an ...
val-target 就是这个矩形值和目标值的差距,使用这个 TreeSet 的 ceiling 方法(这也是使用 TreeSet 的原因,查找的复杂度是 log n),去找一个必须大于等于这个差距的最小值 subres。这里减去 target 再去 TreeSet 里面找就是为了保证在计算差距的时候始终预留好目标值的空间。
Explanation: Because the sum of rectangle [[0, 1], [-2, 3]] is 2, and 2 is the max number no larger than k (k = 2). Note: 1. The rectangle inside the matrix must have an area > 0. 2. What if the number of rows is much larger than the number of columns?
max(max, maxOfMergeLine); } } @@ -43,25 +51,35 @@ public int maxSumSubmatrix(int[][] matrix, int k) { */ private int getMaxSubArray(int[] nums, int k) { TreeSet<Integer> treeSet = new TreeSet<>(); // 千万注意,将0放入是至关重要的一步!!! // 一旦reeSet.ceiling返回0...
();16intval = 0; //sum array's preSum17set.add(0);18for(intl=0; l<n; l++) {19sum[l] += moreCol?matrix[j][l] : matrix[l][j];20val +=sum[l];21Integer oneSum = set.ceiling(val-k);22if(oneSum !=null) {23res = Math.max(res, val-oneSum);24}25set.add(val);26...