解法1 参照leetcode 122, 解法几乎一样 但这里需要三个数组, sell: 每次卖出股票后自身的收益 buy: 每次买入股票后自身的收益 cooldown: 冷冻股票后自身的收益 根据题意很明显:cooldown[i] = sell[i-1] 因为题目说在卖出之后需要一个冷冻期 sell[i] = max( sell[i-1], buy[i-1] + prices[i] )
leetcode 309 Best Time to Buy and Sell Stock with Cooldown 详细解答 解法1参照leetcode122, 解法几乎一样 但这里需要三个数组,sell: 每次卖出股票后自身的收益buy: 每次买入股票后自身的收益cooldown:冷冻股票后自身的收益 根据题意很明显:cooldown[i] =sell[i-1] 因为题目说在卖出之后需要一个冷冻期sell...
首先,对于任意i天开始(注意是第i天开始,第i天的操作还没发生)的时候,有三种可能的状态: S0,手中没有股票,可以买;S1,手中有股票,可以卖;S2,手中没有股票,也不能买,即昨天刚卖,今天cooldown; 在这三种状态下,分别可以执行买卖等操作,即第i天的操作之后,到达第i+1天的状态,转换图如下: 由此,我们从第1...
/* * @lc app=leetcode id=309 lang=javascript * * [309] Best Time to Buy and Sell Stock with Cooldown * *//** * @param {number[]} prices * @return {number} */var maxProfit = function (prices) { if (prices == null || prices.length <= 1) return 0; // 定义状态变量 ...
LeetCode 0309. Best Time to Buy and Sell Stock with Cooldown最佳买卖股票时机含冷冻期【Medium】【Python】【动态规划】 Problem LeetCode Say you have an array for which theith element is the price of a given stock on dayi. Design an algorithm to find the maximum profit. You may complete ...
Can you solve this real interview question? Best Time to Buy and Sell Stock with Cooldown - You are given an array prices where prices[i] is the price of a given stock on the ith day. Find the maximum profit you can achieve. You may complete as many tra
【leetcode】45-best-time-to-buy-and-sell-stock-with-cooldown 力扣 714. 买卖股票的最佳时机包含手续费 开源地址 为了便于大家学习,所有实现均已开源。欢迎 fork + star~ https://github.com/houbb/leetcode 122. 买卖股票的最佳时机 II 给你一个整数数组 prices ,其中 prices[i] 表示某支股票第 i 天...
LeetCode 309. Best Time to Buy and Sell Stock with Cooldown (DP),题目动态规划dp[i][0]表示当天什么都不操作dp[i][1]表示当天买进dp[i][2]表示当天卖出状态转移就好写出了classSolution{public:longlongintdp[10005][3];intmaxProfit(vector<int>&
buy[i]: To make a decision whether to buy ati, we either take a rest, by just using the old decision ati - 1, or sell at/beforei - 2, then buy ati, We cannot sell ati - 1, then buy ati, because of cooldown. sell[i]: To make a decision whether to sell ati, we either ...
【解答】“Best Time to Buy and Sell Stock”,也算是经典题了。这个题改变的地方在于,设置了一个 cooldown 的限制。想了好些办法,下面这个我认为最清晰的解答的思路来源于这篇文章。 分别建立 buy、sell、rest 三个数组,长度都为 2,分别表示昨天和今天的情况。根据奇数天和偶数天的不同,数组的第 0 项和第...