You are given twonon-emptylinked lists representing two non-negative integers. The digits are stored inreverse orderand each of their nodes contain a single digit. 如果,我们将这两个数相加起来,则会返回一个新的链表来表示它们的和。 Add the two numbers and return it as a linked list. 您可以...
# class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def addTwoNumbers(self, l1: Optional[ListNode], l2: Optional[ListNode]) -> Optional[ListNode]: # 哨兵结点,方便后续处理 head_pre = ListNode(0) # 结果链表的尾结点,方便...
}structListNode*addTwoNumbers(structListNode* l1,structListNode* l2) { int carry =0;structListNode* newlist =IniNode(0);structListNode* p = newlist;structListNode* newp;structListNode* p1 = l1;structListNode* p2 = l2; int flag =0;while(true) {// BreakJudgingif(p1 == NULL && p2 ==...
next(NULL) {}* };*/class Solution {public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { struct ListNode * node= new struct ListNode(0) ; struct ListNode *p=l1,*q=l2,*root=node; int carry=0; while
/*** Definition for singly-linked list.* public class ListNode {* public int val;* public ListNode next;* public ListNode(int x) { val = x; }* }*/publicclassSolution{publicListNodeAddTwoNumbers(ListNodel1,ListNodel2){ListNodehead=newListNode(0);ListNodel3=head;ListNodel4=l3;intcurrentSum...
1classSolution {2public:3ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {4ListNode *res =newListNode(-1);5ListNode *cur =res;6intcarry =0;7while(l1 ||l2) {8intn1 = l1 ? l1->val :0;9intn2 = l2 ? l2->val :0;10intsum = n1 + n2 +carry;11carry = sum /10;12cur-...
LeetCode 2. Add Two Numbers non-empty You may assume the two numbers do not contain any leading zero, except the number 0 itself. Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: answer: class Solution { public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {...
digits数字stored in reverse反向存储 each of每一个nodes节点 3 惊人而又蹩脚的中文翻译 本题主要是类似数据在机器中存储的方式,我们平常所见的数据比如342,在链表中是逆向存储的所以就成了2->4->3这样了,同样5 -> 6 -> 4就是465, 如果这样转换后,我们就会发现342+465=807,在十位上相加是超过10向前进一...
Leetcode:Add Two Numbers分析和实现 Add Two Numbers这个问题的意思是,提供两条链表,每条链表表示一个十进制整数,其每一位对应链表的一个结点。比如345表示为链表5->4->3。而我们需要做的就是将两条链表代表的整数加起来,并创建一个新的链表并返回,新链表代表加总值。
代码运行次数:0 运行 AI代码解释 1ListNode*addTwoNumbers(ListNode*l1,ListNode*l2){2int sum=0;3int i=1;4while(l1!=NULL&&l2!=NULL)5{6sum+=i*(l1->val+l2->val);7i*=10;8l1=l1->next;9l2=l2->next;10}11while(l1!=NULL)12{13sum+=i*(l1->val);14i*=10;15l1=l1->next;16}17...