Console.ReadKey(); }publicstaticListNode AddTwoNumbers(ListNode l1, ListNode l2) { ListNode node1=l1; ListNode node2=l2;intsum; ListNode retur=newListNode(0);//關鍵這行,讓tmp & retur 指到同樣的地方,然後只更新tmpListNode tmp
Solution s=newSolution(); tmp=s.addTwoNumbers(node1, node2);while(tmp !=null) { System.out.format("%d ", tmp.val); tmp=tmp.next; } }publicListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode head=newListNode(0); ListNode cur_node=head;intcarry = 0;while(l1 !=null|| l2...
Add the two numbers and return i...Leetcode Algorithms : 2. Add Two Numbers Description You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers ......
cur 指针位置随着赋值而更新,但是dummy指针位置不变。 classSolution(object):defaddTwoNumbers(self,l1,l2):""":type l1: ListNode:type l2: ListNode:rtype: ListNode"""carry=0cur=dummy=ListNode(0)#遍历l1, l2 链表,并依次赋值给cur 节点whilel1orl2:ifl1andl2:ifl1.val+l2.val+carry>=10:cur.nex...
3 输入与输出：/*** Definition for singly-linked list.* struct ListNode {* int val;* ListNode *next;* ListNode(int x) : val(x), next(NULL) {}* };*/class Solution {public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { }};4 解决思路：从表头开始相加，记录每次相加...
1classSolution {2public:3ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {4ListNode *res =newListNode(-1);5ListNode *cur =res;6intcarry =0;7while(l1 ||l2) {8intn1 = l1 ? l1->val :0;9intn2 = l2 ? l2->val :0;10intsum = n1 + n2 +carry;11carry = sum /10;12cur-...
Can you solve this real interview question? Add Two Numbers - You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers an
天是来自LeetCode的第2题:两数相加(Add Two Numbers) 注意:这里说的两数字,是来自两个非空的链表,而不是简单的加法运算哦。 No2. 两数相加(Add Two Numbers) 题目: 给你两个 非空 的链表,表示两个非负的整数。它们每位数字都是按照 逆序 的方式存储的,并且每个节点只能存储 一位 数字。 请你将两个数...
LeetCode 2. Add Two Numbers non-empty You may assume the two numbers do not contain any leading zero, except the number 0 itself. Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: answer: class Solution { public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {...
digits数字stored in reverse反向存储 each of每一个nodes节点 3 惊人而又蹩脚的中文翻译 本题主要是类似数据在机器中存储的方式,我们平常所见的数据比如342,在链表中是逆向存储的所以就成了2->4->3这样了,同样5 -> 6 -> 4就是465, 如果这样转换后,我们就会发现342+465=807,在十位上相加是超过10向前进一...