欢迎访问原文所在博客:https://52heartz.top/articles/leetcode-76-minimum-window-substring/ 解答1[Java]: 思路 注意 if (map[s.charAt(right++)]-- > 0) 这句,不论 right 指向位置的字符是哪个,在判断之后都会被减去 1。因为在前边的语句中,已经预先把 t 中的字符在 map 中加 ...Leet...
【LeetCode】76. Minimum Window Substring Minimum Window Substring Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). For example, S ="ADOBECODEBANC" T ="ABC" Minimum window is"BANC". Note: If there is no s...
public String minWindow(String s, String t) { if (s == null || t == null) { return ""; } int[] map = new int[128]; int left = 0; int right = 0; int start = -1; int len = s.length() + 1; int match = t.length(); for (int i = 0; i < t.length(); i++...
LeetCode 76_Minimum Window Substring https://leetcode.cn/problems/minimum-window-substring/ 一、个人版本 public class Solution1 { public String minWindow(String s, String t) { Balance balance = new Balance(s, t); Integer[] idxList = balance.idxList; if (idxList.length == 0 || idxList...
func minWindow(s string, t string) string { m := len(s) // count[ch] 表示滑动窗口 [l, r) 中字母 ch 还需出现的次数 count := make(map[byte]int) // 初始化为 t 中每个字母的出现次数 for _, ch := range t { count[byte(ch)] += 1 } // remain 表示滑动窗口 [l, r) 中还...
[LeetCode, deprecated] 76. Minimum Window Substring 最小窗口子串。题意是给两个字符串S和T,T比较短。请输出一个最小的S的子串,包含了T中出现的所有字母。例子, Example: Input: S = "ADOBECODEBANC", T = "ABC" Output: "BANC" 这个题因为有时间复杂度的要求所以只能用到一个叫做滑动窗口的思想。
If there is such window, you are guaranteed that there will always be only one unique minimum window in S. 最小覆盖子串。题意是给两个字符串S和T,S较长,请找出S中最短的包含T中所有字母的子串。思路依然是滑动窗口(sliding window),这个题解是具有普适性的,可以套用到多个LC的题目中。如下是几个...
classSolution{ public: stringminWindow(strings,stringt) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 s = "ADOBECODEBANC" t = "ABC" 9 1 2 3 4 5 6 › "ADOBECODEBANC" "ABC" "a" "a" "a" "aa" Source...
本文始发于个人公众号: TechFlow,原创不易,求个关注 今天是 LeetCode专题的第45篇文章,我们一起来看看LeetCode的76题,最小窗口子串Minimum Window Substring。 这题的官方难度是 Hard,通过了也是34.2%,4202…
https://leetcode-cn.com/problems/minimum-window-substring/ Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). 题意 给你一个字符串 S、一个字符串 T 。请你设计一种算法,可以在 O(n) 的时间复杂度内,从字符串 ...