LeetCode 468. 验证IP地址 技术标签: LeetCode1. 题目编写一个函数来验证输入的字符串是否是有效的 IPv4 或 IPv6 地址。IPv4 地址由十进制数和点来表示,每个地址包含4个十进制数,其范围为 0 - 255, 用(".")分割。比如,172.16.254.1;同时,IPv4 地址内的数不会以 0 开头。比如,地址 172.16.254.01 是不...
classSolution{publicStringvalidIPAddress(StringIP){if(isIp4(IP)){return"IPv4";}if(isIp6(IP)){return"IPv6";}return"Neither";}publicbooleanisIp4(String ip){ip=ip.trim();if(ip.contains(".")){for(int i=0;i<ip.length();i++){char c=ip.charAt(i);if(c!='.'&&!Character.isDigit(...
https://leetcode.cn/problems/target-sum/solution/gong-shui-san-xie-yi-ti-si-jie-dfs-ji-yi-e...
【排序】https://leetcode-cn.com/problems/sort-an-array/solution/pai-xu-shu-zu-by-leetcode-sol...
class Solution { public: int getCount(map<int, int> &hmap, int value, bool asc){ int count = 0; while(hmap.find(value) != hmap.end()){ hmap.erase(value); count++; if(asc){ value++; } else { value--; } } return count; } int longestConsecutive(vector<int> &num) { // ...
1classSolution {2public:3voidreverseWords(string&s) {4stringstream iss(s);5stringtemp;6iss >>s;7while(iss >>temp) {8s = temp +""+s;9}10if(isspace(s[0])) {s ="";}11return;12}13}; 【157】Read N Characters Given Read4 ...
示例 1: code class Solution { public int numWaterBottle 阅读全文 » 2021215 LeetCode刷题 比特位计数(难度 :单词规律) 发表于 2021-12-15 20:41阅读:28评论:0推荐:0 摘要:题目: 给你一个整数 n ,对于 0 <= i <= n 中的每个 i ,计算其二进制表示中 1 的个数 ,返回一个长度为 n + 1...
详细易懂的讲解单调栈 https://leetcode-cn.com/problems/daily-temperatures/solution/javadan-diao-zhan-ni-xu-bian-li-by-hyh-2/ 相关链接 1, https://www.cnblogs.com/Atanisi/p/7563178.html 2, https://blog.csdn.net/qq_17550379/article/details/86519771 3, https://www.cnblogs.com/1024th/p...
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class Solution { public int maxProfit(int[] prices) { if(prices.length==0) return 0; //用后面的减去前面的,随时更新前面的值 //最后得到一个最大值 int front; front=prices[0]; int res=0; for(int i=1;i<prices.length;i++){