示例 1: code class Solution { public int numWaterBottle 阅读全文 » 2021215 LeetCode刷题 比特位计数(难度 :单词规律) 发表于 2021-12-15 20:41阅读:28评论:0推荐:0 摘要:题目: 给你一个整数 n ,对于 0 <= i <= n 中的每个 i ,计算其二进制表示中 1 的个数 ,返回一个长度为 n + 1...
class Solution(): def rotate(self, matrix): matrix.reverse() for i in range(len(matrix)-1): for j in range(i+1, len(matrix[0])): matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j] if __name__ == "__main__": x = [[1, 2, 3], [4, 5, 6], [7, ...
以这样的方式得到的xi会无限趋近于f(x)=0的解。 判断xi是否是f(x)=0的解有两种方法: 一是直接计算f(xi)的值判断是否为0, 二是判断前后两个解xi和xi-1是否无限接近。 经过(xi, f(xi))这个点的切线方程为f(x) = f(xi) + f’(xi)(x - xi),其中f'(x)为f(x)的导数,本题中为2x。令切线...
class Solution { public: int trap(vector<int>& height) { if(height.empty()) return 0; height.push_back(0); int res =0; stack<int> st;//decreasing stack for(int i = 0; i<height.size();++i){ while(!st.empty() && height[i] > height[st.top()]){ ...
文章作者:Tyan 博客:noahsnail.com | CSDN | 简书 1. Description 2. Solution Reference https://leetcode.com/problems/island-perimeter/description/ PAT : 数据结构与算法题目集(中文)7-6 列出连通集 C++11: DFS/BFS遍历图需熟练～ END [leetcode]934. Shortest Bridge least 1.) Explanation: 先用...
[LeetCode] 297 二叉树的序列化与反序列化 297. 二叉树的序列化与反序列化 - 力扣(LeetCode) (leetcode-cn.com) 题意:给定二叉树,将各个结点值转化为字符串(包括中间的空结点,记为“None”);给定序列化字符串,转化为对应的二叉树。 注意:序列化时对树的遍历顺序,要与反序列化时建树的顺序保持一致。
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class Solution { public int climbStairs(int n) { return calcWays(n); } priv...
end(), s.begin(), [](unsigned char c) { return std::toupper(c); }); std::cout << s << std::endl; // HELLO // binary例子:把foo和bar两个vector相加结果保存在foo,结果为5个3 std::vector<int> foo(5, 1); std::vector<int> bar(5, 2); // std::plus adds together its two...