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简介:【leetcode报错】 leetcode格式问题解决:error: stray ‘\302’ in program [solution.c] 一、情景再现 二、报错原因 该错误是指源程序中有非法字符,需要将非法字符去掉。 一般是由于coder1.使用中文输入法或者2.从别的地方直接复制粘贴代码造成的。 代码中出现了中文空格,中文引号,各种中文标点符号都会出现,...
#Title中文站SolutionCode 0001 Two Sum 两数之和 README C++ 0002 Add Two Numbers 两数相加 README C++ 0003 Longest Substring Without Repeating Characters 无重复字符的最长子串 README C++ 0004 Median of Two Sorted Arrays 寻找两个有序数组的中位数 README C++ 0005 Longest Palindromic Substring 最长回...
Core: A XOR B XOR A XOR C XOR B = C, Use Bit with different value in the two single value to regist each value in list(otherwise, divide list with the regist bit) Reference:https://discuss.leetcode.com/topic/21605/accepted-c-java-o-n-time-o-1-space-easy-solution-with-detail-exp...
Elements in a quadruplet (a,b,c,d) must be in non-descending order. (ie,a≤b≤c≤d) The solution set must not contain duplicate quadruplets. For example, given array S = {1 0 -1 0 -2 2}, and target = 0. A solution set is: ...
Example: Given array nums = [-1, 0, 1, 2, -1, -4], A solution set is: [ [-1, 0, 1], [-1, -1, 2] ] 题目解析: 题目可以分解为两个子问题: 1、找到整数a、b、c,使得a+b+c=0; 2、重复的a、b、c只输出一次; 子问题1同样可以分解为两个问题:1、找到两个整数a、b,判断c=-...
class Solution: def twoSum(self,nums,target): nums_hash = {} for index,number in enumerate(nums): one_num = nums[index] other_num = target-one_num if other_num in nums_hash: return [nums_hash[other_num],index] nums_hash[number] = index return [] 手动推演: nums = [2,6,8,9...
Parts of the problems don't provide C interface for solution, so I accomplished them with C++ Language. CompileCfiles using command: CompileC++files using command: g++ -std=c++11 -Wall src/bar.cpp -o bar OR You can build all the files usingmake(Use MinGW GCC and GNU Make on Windows)....
class Solution: def diffWaysToCompute(self, input: str) -> List[int]: # 如果只有数字,直接返回 if input.isdigit(): return [int(input)] res = [] for i, char in enumerate(input): if char in ['+', '-', '*']: # 1.分解:遇到运算符,计算左右两侧的结果集 # 2.解决:diffWaysToCom...
class Solution: def maxSubarrays(self, nums: List[int]) -> int: if reduce(iand, nums): return 1 cnt = 0 curr = (1 << 20) - 1 for num in nums: curr &= num if curr == 0: cnt += 1; curr = (1 << 20) - 1 return cnt Biweekly Contest 115 2901. Longest Unequal Adjac...