AI代码解释 publicclassSolution{publicListNodereverseBetween(ListNode head,int m,int n){if(m==n||head==null||head.next==null){returnhead;}ListNode pre=newListNode(0);pre.next=head;ListNode Mpre=pre;ListNode NodeM=head;ListNode NodeN=head;int mNum=1;int nNum=1;while(mNum<m&&NodeM!=nu...
一时之间没有想到怎样做reverse比较好,参考了一下网上的思路,发现这样做比较好:还是要用Runner Technique,还是要用Dummy Node;两个指针: npointer指到n的位置,mpointer指到m的前一位;每一次把mpointer后一位的元素放到npointer的后一位:mpointer.next.next = npointer.next;直到mpointer.next = npointer为止(m与...
*@return*/publicNodereverse(Node head,intm,intn){if(head ==null) {returnhead; }Nodedummy=newNode(); dummy.next = head;intpos=1;NodeunreverseListLast=dummy;NodereverseListLast=null;Nodecur=head;Nodenext=null;Nodepre=dummy;while(cur !=null&& pos <= n) { next = cur.next;if(pos =...
publicclassSolution{publicListNodeReverseList(ListNode head){if(head==null)returnnull;//head为当前节点,如果当前节点为空的话,那就什么也不做,直接返回null;ListNode pre=null;ListNode nextnode=null;while(head!=null){nextnode=head.next;head.next=pre;pre=head;head=nextnode;}returnpre;}} Reverse Lin...
问题链接英文网站:92. Reverse Linked List II中文网站:92. 反转链表 II问题描述Given the head of a singly linked list and two integers left and right where left <= right, reverse the nodes of the l…
Reverse Linked List的延伸题。 可以考虑取出需要反转的这一小段链表,反转完后再插入到原先的链表中。 以本题为例:变换的是 2,3,4这三个点,那么我们可以先取出 2 ,用 front 指针指向2 ,然后当取出 3 的时候,我们把 3 加到 2 的前面,把 front 指针前移到 3 ,依次类推,到 4 后停止,这样我们得到一个...
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: Given m, n satisfy ...
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: ...
{:align=center}第2 步完成以后「拉直」的效果如下:{:align=center}第3 步,同理。{:align=center}第3 步完成以后「拉直」的效果如下:{:align=center}代码C++ Java Python3 Golang C JavaScriptclass Solution { public: ListNode *reverseBetween(ListNode *head, int left, int right) { ...
Reverse a singly linked list. click to show more hints. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 递归法 复杂度 时间O(N) 空间 O(N) 递归栈空间 思路 基本递归 代码 public class Solution { ...