anagram的意思是:abc,bac,acb就是anagram。即同一段字符串的字母的不同排序。将这些都找出来。这里使用了哈希表,即Python中的dict。针对前面的例子来讲,映射为{abc:abc,bac,acb}。 my code: class Solution(object): def groupAnagrams(self, strs): """ :type strs: List[str] :rtype: List[List[str...
2. 通过新数组,结合multimap(元素值,在数组中的索引值)来定位新数组相同(原数组相似)的元素位置。 3. 遍历这个map将相似的元素放入结果数组中即可。 classSolution {public: vector<vector<string>> groupAnagrams(vector<string>&strs) { vector<vector<string>>res;if(strs.empty())returnres;intn =strs.s...
【Leetcode】Group Anagrams https://leetcode.com/problems/anagrams/ 题目: Given an array of strings, group anagrams together. ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat","tea"], ["nat","tan"], ["bat"] ] 1. 2. 3. 4. 5. Note: For the ret...
1classSolution {2public:3vector<vector<string>> groupAnagrams(vector<string>&strs) {4vector<vector<string> >res;5if(strs.size() ==0)returnres;6unordered_map<string, vector<string> >dict;7for(inti =0, n = strs.size(); i < n; i++)8{9stringtem =strs[i];10sort(tem.begin()...
【摘要】 Leetcode 题目解析之 Group Anagrams Given an array of strings, group anagrams together. For example, given: “eat”, “tea”, “tan”, “ate”, “nat”, “bat”, Return: [ “ate”, “eat”,“tea”, “nat”,“tan”, ...
class Solution { public: vector<vector<string>> groupAnagrams(vector<string>& strs) { unordered_map<string, vector<string>> mp; for (string& str: strs) { string key = str; sort(key.begin(), key.end()); mp[key].emplace_back(str); } vector<vector<string>> ans; for (auto it ...
解法一: classSolution {public: vector<vector<string>> groupAnagrams(vector<string>&strs) { vector<vector<string>>res; unordered_map<string, vector<string>>m;for(stringstr : strs) {stringt =str; sort(t.begin(), t.end()); m[t].push_back(str); ...
class Solution { public List<List<String>> groupAnagrams(String[] strs) { Map<String, List<String>> map = new HashMap(); for (String str : strs) { char[] sc = str.toCharArray(); Arrays.sort(sc); String key = new String(sc); if (map.get(key) == null) { List list = new...
2020年10月22日 12:272621浏览·8点赞·0评论 爱学习的饲养员 粉丝:7.0万文章:46 关注 视频讲解 622:17 Leetcode力扣 1-300题视频讲解合集|手画图解版+代码【持续更新ing】 84.9万800 视频爱学习的饲养员 排序法 Python3代码 Java代码 计数法 Python3代码 ...
LeetCode 49: 字母异位词分组 Group Anagrams 题目: 给定一个字符串数组,将字母异位词组合在一起。字母异位词指字母相同,但排列不同的字符串。 Given an array of strings, group anagrams together. 示例: 输入: ["eat", "tea", "tan", "ate", "nat", "bat"], ...