第四章 LeetCode 题解 0001~0099 0100~0199 0200~0299 0300~0399 0400~0499 0500~0599 0600~0699 0700~0799 0800~0899 0900~0999 1000~1099 1100~1199 1200~1299 1300~1399 1400~1499 1500~1599 1600~1699 1700~1799 1800~1899 1900
https://leetcode.com/problems/subsets/discuss/27288/My-solution-using-bit-manipulation 题解的解释参考:https://www.mathsisfun.com/sets/power-set.html(有点像状态压缩的感觉) bit manipulation 【136】Single Number(2018年11月4日)(剑指offer上有个变种题,有两个数只出现了一次,求出出现一次的这两个数...
xor= xor >> 1; } } }returnsum; } 2.更快的做法 publicinttotalHammingDistance(int[] nums) {inttotal = 0, n =nums.length;for(intj=0;j<32;j++) {intbitCount = 0;for(inti=0;i<n;i++) bitCount+= (nums[i] >> j) & 1; total+= bitCount*(n -bitCount); }returntotal; } 这...
进度 0/273 已解答 0% 通过率 击败用户 0% 击败用户 0% 击败用户 0% 0尝试中 0次提交 0尝试中 0尝试中 0尝试中 简单 0/63 中等 0/124 困难 0/86 讨论 29. 两数相除 22.4% 中等 67. 二进制求和 53.9% 简单 78. 子集 82.3% 中等
2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. Solution 1: Bit Manipulation: 这题真心有点难,get the max XOR bit by bit note that if A^B=C, then A^C=B, B^C=A 1publicclassSolution {2publicintfindMaximumXOR(int[] nums) {3intmask = 0, max = 0;4for(inti=31; i>=0;...
用到了mask(掩码),目的是在bit manipulation时可以逐个bit判断每一位是否为1。当我们传进来一个十进制数字,如28时,它在计算机里是用二进制表达为... 0001 1100的,当使用mask: ... 0000 1111(15)时,因为是全1,并且1111之前的数字为全0,所以不管这个数字后四位以前的bit是什么内容,最终对会被记作0,这也就...
LeetCode-Bit Manipulation-371-E:两整数之和(Sum of Two Integers),代码先锋网,一个为软件开发程序员提供代码片段和技术文章聚合的网站。
Bit Manipulation Find the Difference /* * Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. ...
If this function is called many times, how would you optimize it? 这个题目就是利用Bit Manipulation, 依次将每位n的最后一位移到ans的前面, T: O(1) Code classSolution:defreverseBits(self, n): ans=0for_inrange(32): ans= (ans<<1) + (n&1) ...
The given number is guaranteed to fit within the range of a 32-bit signed integer. You must not useanymethod provided by the library which converts/formats the number to hex directly. Example 1: Input: 26 Output: "1a" Example 2: ...