1.用一个boolean数组prime,N/2大小,用来表示3,5,7,9,11,13,15,17,19...等的奇数(因为偶数不可能成为素数,2除外) 均置为prime[i] = true 2.然后进行判断, i = 0时,由于prime[0]=true(3); 则将数组内 i + (2 * i + 3) * j < sqrt(N) 的数置为false(为合数), prime[3] = (9) ...
和第二种解法的思路类似,将20个数变成布尔类型的数组,计算出二进制数中1的个数当做数组的下标去匹配。 publicintcountPrimeSetBits3(intL,intR){intcount=0;boolean[] arr = {false,false,true,true,false,true,false,true,false,false,false,true,false,true,false,false,false,true,false,true};for(inti=L...
762. Prime Number of Set Bits in Binary Representation Given two integers L and R, find the count of numbers in the range [L, R] (inclusive) having a prime number of set bits in their binary representation.(Recall that the number of set bits an integer has is the number of 1s presen...
762. Prime Number of Set Bits in Binary Representation solution1: class Solution { public: int countPrimeSetBits(int L, int R) { int res = 0; int bits = 0; for(int i=L; i<=R; i++) { bits = countBits(i); if(isPrime(bits) && bits!=1 ) res++;//err... ...
示例说明请见LeetCode官网。来源：力扣（LeetCode） 链接：https://leetcode-cn.com/problems/perfect-number/ 著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。解法一：解法一添加一个获取num所有正因子（除了它本身）的方法calculateAllPrimeFactor，返回值是一个List，将返回值所有的元素相加...
Leetcode学习笔记(3) 题目1 ID88 给你两个有序整数数组 nums1 和 nums2,请你将 nums2 合并到 nums1 中,使 num1 成为一个有序数组。 说明: 初始化 nums1 和 nums2 的元素数量分别为 m 和 n 。 你可以假设 nums1 有足够的空间(空间大小大于或等于 m + n)来保存 nums2 中的元素。
Except for the first two numbers, each subsequent number in the sequence must be the sum of the preceding two. For example: "112358" is an additive number because the digits can form an additive sequence: 1, 1, 2, 3, 5, 8. 代码语言:javascript 代码运行次数:0 运行 复制 1 + 1 ...
Number of 1 Bits 参考资料: https://leetcode.com/problems/prime-number-of-set-bits-in-binary-representation/discuss/113225/Short-C++-12-ms https://leetcode.com/problems/prime-number-of-set-bits-in-binary-representation/discuss/113227/JavaC++-Clean-Code ...
Java 素数 prime numbers-LeetCode 204 Description: Count the number of prime numbers less than a non-negative number, n click to show more hints. Credits: Special thanks to@mithmattfor adding this problem and creating all test cases. 求n以内的所有素数,以前看过的一道题目,通过将所有非素数标记...
Count Primes -- leetcode 文章标签时间复杂度i++文章分类C/C++后端开发 Description: Count the number of prime numbers less than a non-negative number, n. 基本思路:筛法 1。 2 为素数。 筛掉以2为因子的数。 即2 * 2, 2*3, 2*4,2*5...