Yes, use a deque to maintain the index in the sliding window. We want to make sure we maintain the deque such that the first element in deque is always the index to the max element in sliding window. How? every time before we append a new index j into deque, we first check from t...
这就是关于提高链表性能的 15 个最重要的 Leetcode 问题。掌握这些链表问题不仅能让你为常见的面试问题做好准备,还能增强你对链表操作和技术的整体理解。 Practice these problems, understand the underlying concepts, and you’ll be ready to tackle any linked list challenges in your technical interviews. ...
允许输入序列元素有重的变种(见LeetCode 81.选择排序数组的指定值):与元素不可重的实现一样,只不过多了一步首尾元素一样时的去重操作。 View Code 2、升序序列循环左移(右移也可,实现完全一样;可以是0位,此时是有序序列;元素不可重)若干位后查找最值(见LeetCode153.旋转排序数组的最小值): (总结:利用局...
Each pattern is accompanied by a detailed explanation, a sample problem, a solution, and 10 similar LeetCode problems to practice. This comprehensive coverage ensures that you have a solid understanding of each pattern and can apply it effectively in various problem-solving scenarios. Remember, lear...
Level up your coding skills and quickly land a job. This is the best place to expand your knowledge and get prepared for your next interview.
Leetcode题目practice 目录 Leetcode题目解答 1. 删除最外层的括号 2. 两数之和 3. 宝石与石头 4. 移除元素 5.删除排序数组中的重复项 6.寻找两个有序数组的中位数 7.盛最多水的容器 8.存在重复元素 Leetcode题目解答 1. 删除最外层的括号 有效括号字符串为空("")、"(" + A + ")" 或 A + B...
所以,为了提高大家的算法能力,这个公众号后续每天带大家做一道算法题,题目就从LeetCode上面选 ! 今天和大家聊的问题叫做最短单词距离,我们先来看题面:/problems/shortest-word-distance/ Given a list of words and two words word1 and word2, return the shortest distance between these two words in the ...
如何优化LeetCode 664题的算法? 有台奇怪的打印机有以下两个特殊要求: 打印机每次只能打印由 同一个字符 组成的序列。每次可以在任意起始和结束位置打印新字符,并且会覆盖掉原来已有的字符。给你一个字符串 s ,你的任务是计算这个打印机打印它需要的最少打印次数。 示例1: 代码语言:javascript 代码运行次数:0 运...
By the second attempt, you may discover some new tricks or new methods. By the third time, you should find that your code appear to be more concise compared to your first attempt. If so, congratulations! Remember:Deliberate practice does not mean looking for answers and memorizing it. You ...
疯言**疯语 上传 leetcode 示例1:输入:n = 4输出:false解释:如果堆中有 4 块石头,那么你永远不会赢得比赛;因为无论你拿走 1 块、2 块 还是 3 块石头,最后一块石头总点赞(0) 踩踩(0) 反馈 所需:1 积分 电信网络下载 2024年中国1,2-环氧丁烷行业研究报告.docx ...