Related to least common multiples:lowest common multiple least common multiple n.Abbr.lcm The smallest quantity that is divisible by two or more given quantities without a remainder:12 is the least common multiple of 2, 3, 4, and 6.Also calledlowest common multiple. ...
百度试题 结果1 题目【题目】T he least common multiple of 1, 2, 3, 4, 5, 6, 7, 8,9, and 10 is().A.3628800B.7560C.2520D.1260 相关知识点: 试题来源: 解析 【解析】C
A. 360 B. 240 C. 60 D. 120 相关知识点: 试题来源: 解析 D 120 is smallest choice divisible by 6、8、10, and 12. 6、8、10和12的最小公倍数是( ). A.360 B.240 C.60 D.120 120是可以被6、8、10、12整除的最小值. 故选D....
least common multipleA graph G without isolated vertices is a least common multiple of two graphs H1 and H2 if G is a smallest graph,in terms of number of edges,such that there exists a decomposition of G into edge disjoint copies of H1 and H2.The collection of all least common ...
What is the least common multiple of 84 and 112( ). A. 28 B. 196 C. 336 D. 9408 相关知识点: 试题来源: 解析 C 本题题意为“84和112的最小公倍数是多少?”,本题考查因数分解,84与112的最小公倍数为2×2×7×3×4=336. 故选C....
百度试题 结果1 题目The least common multiple of 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 is( ). A. 1B. 1260C. 2520D. 3628800相关知识点: 试题来源: 解析 C
B. 8C. 14D. 64相关知识点: 试题来源: 解析 B Since 8 is already a multiple of both 2 and 4, the lcm is 8. 数字2,4和的最小公倍数是多少( )? A.2 B.8 C.14 D.64 因为8已经是2和4的倍数,所以它们设的最小公倍数是8. 故选B....
My code below works for small ranges only, not something like [1,13] (which is the range 1,2,3,4,5,6,7,8,9,10,11,12,13), which causes a stack overflow. How can I efficiently find the least common multiple of a range? function leastCommonMultiple(arr) { var minn, max; ...
Least Common Multiple (最小公倍数,先除再乘),思路:求第一个和第二个元素的最小公倍数,然后拿求得的最小公倍数和第三个元素求最小公倍数,继续下去,直到没有元素注意:通过最大公约数求最小公倍数的时候,先除再乘,避免溢出1#include<iostream>2#include<cmath>3#inc
最小公倍数(Least Common Multiple) 最小公倍数=两个数的乘积/两个数的最大公约数。 接上篇求最大公约数方法,最小公倍数的代码例如以下: public class LCM { //最小公倍数=两数乘积/最大公约数 public static int lcm(int m, int n){ return m*n/GCD.gcd(m,n);...