A. 360 B. 240 C. 60 D. 120 相关知识点: 试题来源: 解析 D 120 is smallest choice divisible by 6、8、10, and 12. 6、8、10和12的最小公倍数是( ). A.360 B.240 C.60 D.120 120是可以被6、8、10、12整除的最小值. 故选D....
百度试题 结果1 题目【题目】T he least common multiple of 1, 2, 3, 4, 5, 6, 7, 8,9, and 10 is().A.3628800B.7560C.2520D.1260 相关知识点: 试题来源: 解析 【解析】C
Related to least common multiples:lowest common multiple least common multiple n.Abbr.lcm The smallest quantity that is divisible by two or more given quantities without a remainder:12 is the least common multiple of 2, 3, 4, and 6.Also calledlowest common multiple. ...
百度试题 结果1 题目The least common multiple of 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 is( ). A. 1B. 1260C. 2520D. 3628800相关知识点: 试题来源: 解析 C
Least common multiple can be found by multiplying the highest exponent prime factors of 6020 and 6029. First we will calculate the prime factors of 6020 and 6029.Prime Factorization of 6020Prime factors of 6020 are 2, 5, 7, 43. Prime factorization of 6020 in exponential form is: 6020 = ...
My code below works for small ranges only, not something like [1,13] (which is the range 1,2,3,4,5,6,7,8,9,10,11,12,13), which causes a stack overflow. How can I efficiently find the least common multiple of a range? function leastCommonMultiple(arr) { var minn, max; ...
Least Common Multiple (最小公倍数,先除再乘),思路:求第一个和第二个元素的最小公倍数,然后拿求得的最小公倍数和第三个元素求最小公倍数,继续下去,直到没有元素注意:通过最大公约数求最小公倍数的时候,先除再乘,避免溢出1#include<iostream>2#include<cmath>3#inc
thousands of dollars, taking months to complete, themostcommonaresmall projectswithmultipleclients on a day-to-day basis. daccess-ods.un.org daccess-ods.un.org 尽管有些项目可以高达数万美元,需要几个 月才能完成,但最常见的是日常有多个客户端的小项目。
24 IS THE LEAST COMMON MULTIPLE OF 4 AND 6问题补充:匿名 2013-05-23 12:21:38 图24是4和6的最小公倍数 匿名 2013-05-23 12:23:18 24是最常用的多的4和6 匿名 2013-05-23 12:24:58 24是最小公倍数的4和6 匿名 2013-05-23 12:26:38 24 是 4 的最小公倍数和 6 匿名 2013-...
Find six consecutive multiples of 6 whose sum is the least common multiple (LCM) of 13 and 18. Solution 24, 30, 36, 42, 48, and 54. The LCM of 13 and 18 is 13 × 18 = 234, since the numbers are relatively prime. Since we are looking for 6 numbers, we can divide 234 by 6...