思路: 求第一个和第二个元素的最小公倍数,然后拿求得的最小公倍数和第三个元素求最小公倍数,继续下去,直到没有元素 注意:通过最大公约数求最小公倍数的时候,先除再乘,避免溢出 1#include <iostream>2#include <cmath>3#include <cstdio>4#include <vector>5#include <string.h>6#include <string>7#...
2 #include <cmath> 3 #include <cstdio> 4 #include <vector> 5 #include <string.h> 6 #include <string> 7 #include <algorithm> 8 9 using namespace std; 10 11 int gcd(int a, int b) 12 { 13 return b == 0 ? a : gcd(b, a%b); 14 } 15 16 int main() 17 { 18 int n...
百度试题 结果1 题目The least common multiple of 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 is( ). A. 1B. 1260C. 2520D. 3628800相关知识点: 试题来源: 解析 C
The LCM is {{x}^{4}} since {{x}^{4}}=({{x}^{3}})x=({{x}^{2}})({{x}^{2}}).{{x}^{2}}, {{x}^{3}}和{{x}^{4}}的最小公倍数是( ).\text{A}.{{x}^{4}} \text{B}.{{x}^{6}} \text{C}.{{x}^{12}} \text{D}.{{x}^{24}}因为{{x}...
百度试题 结果1 题目【题目】T he least common multiple of 1, 2, 3, 4, 5, 6, 7, 8,9, and 10 is().A.3628800B.7560C.2520D.1260 相关知识点: 试题来源: 解析 【解析】C
答案等于36×6=216结果一 题目 The least common multiple of two integers is 36, and 6 is their greatest common divisor. What is the product of the two numbers?A.6B.16C.72D.108E.216 答案 E相关推荐 1The least common multiple of two integers is 36, and 6 is their greatest common divisor...
the least common multiple of 青云英语翻译 请在下面的文本框内输入文字,然后点击开始翻译按钮进行翻译,如果您看不到结果,请重新翻译! 翻译结果1翻译结果2翻译结果3翻译结果4翻译结果5 翻译结果1复制译文编辑译文朗读译文返回顶部 的最小公倍数 翻译结果2复制译文编辑译文朗读译文返回顶部...
Find the least common multiple and greatest common factor of 30 and 12to the nearest thousandth
My code below works for small ranges only, not something like [1,13] (which is the range 1,2,3,4,5,6,7,8,9,10,11,12,13), which causes a stack overflow. How can I efficiently find the least common multiple of a range? function leastCommonMultiple(arr) { var minn, max; ...
美 英 na.【数】最小公倍数 复数:least common multiples 权威英汉双解 英汉 英英 Least-common-multiple — see also lowest common multiple 例句