(Write a function that takes in a year and returns ‘True’ or ‘False’ whether that year is a leap year. In the Gregorian calendar, three conditions are used to identify leap years:) The year can be evenly divided by 4, is a leap year, unless: The year can be evenly divided by ...
For Leap Year : Condition: Year % 100 != 0 1st Jun 2021, 6:38 PM Tejas Raut - 1 year = int(input()) if(year%4 == 0): if(year%100 == 0): if(year%400 == 0): print("Leap year") else: print("Not a leap year") else: print("Leap year") else: print ("Not a le...
The year is called a leap year in python if this condition is met. If the year is not divisible by 400, it means it’s not a leap year. If the year is not divisible by 100 (as per the second condition), it directly returns True, indicating a leap year. If the year is not div...
You can just check if the year is divisible by 4, this is the only necessary and also sufficient condition to be a leap year. In case the year is not a leap year you can add to it (4- year%4) and you got the next leap year edit: oh I apologize for my ignorance, being divisi...
Year : ")varyear = reader.nextInt();// checking leap year conditionvalisleap =if(year %4==0){if(year %100==0) {// Century Year must be divisible by 400 for Leap yearyear %400==0}elsetrue}elsefalse; println("$year is ${if (isleap) "Leap Year" else "Not a Leap Year"} "...
count = 0 # checking the condition is True or not for year in range(year1, year2): val = calendar.isleap(year) if val == True: lyear = year count += 1 if count >= 1: # print 1th month of first leap year calendar.prmonth(lyear, 1, 2, 1) # Returned False, year is not...
count =0# checking the condition is True or notforyearinrange(year1, year2): val = calendar.isleap(year)ifval ==True: lyear = year count +=1ifcount >=1:# print 1th month of first leap yearcalendar.prmonth(lyear,1,2,1)# Returned False, year is not a leapelse: ...
In the first condition, we check if it is a century leap year, and in the 2nd condition, we check if it is a leap year and not a century year. if ((Useryear % 400 == 0) || ((Useryear % 4 == 0) && (Useryear % 100 != 0))) If both conditions are true, it will pr...
#include <iostream> using namespace std; // create a class class Leap { // declare private data member private: int year; // a public function with a int type parameter public: void leapyear(int y) { // copying parameter value in data members year = y; // if condition to check ...
In this C# program, we are reading the value of year using ‘year’ variable. When A year is divided by 4. If the remainder becomes 0, then the year is called a leap year. advertisement The Nested-If else condition statement is used to check the given year is leap year or not. In...