For Leap Year : Condition: Year % 100 != 0 1st Jun 2021, 6:38 PM Tejas Raut - 1 year = int(input()) if(year%4 == 0): if(year%100 == 0): if(year%400 == 0): print("Leap year") else: print("Not a leap year") else: print("Leap year") else: print ("Not a le...
The year is called a leap year in python if this condition is met. If the year is not divisible by 400, it means it’s not a leap year. If the year is not divisible by 100 (as per the second condition), it directly returns True, indicating a leap year. If the year is not div...
2) Check leap year by simply checking the leap year condition As we know the condition to check the given year is a leap year or not. So, here we will implement the condition and try to write the Python program. Python program to check leap year by checking the condition # input the ...
LI HANthat's because it's notpythonbut C 1st Jun 2021, 6:54 PM ChaoticDawg + 1 TejasIf it passed, then it will be purely circumstantial. Because it should be; if(year % 400 == 0 || (year % 4 == 0 && year % 100 != 0) {} There is no condition in which; year % 400 ...
Enter a year: 20242024 is a leap year Output Evaluating the 3rd Condition: Enter a year: 40004000 qualifies as a leap year Determine Leap Year Through theCalendarModule in Python Python’scalendarmodule is one of the reliable tools to perform computations involving dates. It follows the European...
Another way is to use the nested if statements where each if statement contains one condition. Let us use the nested if statements to create a function that checks whether the given year is a leap year or not. python # creating the functiondefis_leap(year):# variable to check the leap ...
#In this leap year python program, the user to asked enter a year. The program checks whether the entered year is a leap year or not. 1 2 3 4 5 6 7 8 9 10 11 year = int(input("Enter a year: ")) if (year % 4) == 0: ...
Year : ")varyear = reader.nextInt();// checking leap year conditionvalisleap =if(year %4==0){if(year %100==0) {// Century Year must be divisible by 400 for Leap yearyear %400==0}elsetrue}elsefalse; println("$year is ${if (isleap) "Leap Year" else "Not a Leap Year"} "...
# checking the condition is True or not foryearinrange(year1,year2): val=calendar.isleap(year) ifval==True: lyear=year count+=1 ifcount>=1: # print 1th month of first leap year calendar.prmonth(lyear,1,2,1) # Returned False, year is not a leap ...
count =0# checking the condition is True or notforyearinrange(year1, year2): val = calendar.isleap(year)ifval ==True: lyear = year count +=1ifcount >=1:# print 1th month of first leap yearcalendar.prmonth(lyear,1,2,1)# Returned False, year is not a leapelse: ...