Python program to check leap year by using the calendar module # importing the moduleimportcalendar# input the yearyear=int(input('Enter the value of year: '))leap_year=calendar.isleap(year)# checking leap yearifleap_year:# to check conditionprint('The given year is a leap year.')else:...
The output of Leap Year Program In Python: 2024 is a leap year. Also Read: How to check for Armstrong Number in Python? Different Methods to Find Leap Year In Python Programming There are a lot of different methods to find the leap year in the Python Program. Here are a few: i) ...
• The century year is a leap year only if it is perfectly divisible by 400. For example, 2000 is a leap year. Python Program to Check Leap Year #In this leap year python program, the user to asked enter a year. The program checks whether the entered year is a leap year or not....
Write a Python program that checks whether a given year is a leap year or not using boolean logic.Sample Solution:Code:def check_leap_year(year): return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) def main(): try: year = int(input("Input a valid year: "...
Program to check leap year in Kotlin packagecom.includehelp.basicimport java.util.*// Main Method Entry Point of Programfunmain(args: Array<String>) {// InputStream to get Inputvarreader = Scanner(System.`in`)//Input Integer Valueprintln("Enter Year : ")varyear = reader.nextInt();//...
6.程序实现的功能:输人某年某月某日,判断这一天是这一年的第几天,Python代码如下: d e f leap(year):$$ l e a p = 0 $$$ i f ( y e a r \% 4 0 0 = = 0 ) o r ( ( y e a r \% 4 = = 0 ) a n d ( y e a r \% 1 0 0 ! = 0 ) ) : $$$ l e a ...
Python Leap Year #The test case is passing 4/6. I don't know what is wrong with my code, please help year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print("Leap year") else: print("Not a leap year") else: print("Not a leap year...
Hi all, This does not bode too well but I have become stuck on the Leap YearPythonpractice test. Can you please let me know why the below code is not working? This one has got the better of me. year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400...
python # creating the functiondefis_leap(year):# variable to check the leap yearleap =False# using nested if statementsif(year %4) ==0:if(year %100) ==0:if(year %400) ==0: leap =Trueelse: leap =Falseelse: leap =Trueelse: ...
Program 1:=begin Ruby program to check whether the year is leap year or not. =end puts "Enter the year you want to check" yr = gets.chomp.to_i if yr % 400 == 0 puts "#{yr} is a leap year" elsif yr % 4 == 0 && yr % 100 !=0 puts "#{yr} is a leap year" else...