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Description Given two positive integers a and b, we can easily calculate the greatest common divisor (GCD) and the least common multiple (LCM) of a an
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Given two positive integers a and b, we can easily calculate the greatest common divisor (GCD) and the least common multiple (LCM) of a and b. But what about the inverse? That is: given GCD and LCM, finding a and b. Input The input contains multiple test cases, each of which contai...
Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair? Input The first and only line contains an integer Output Print two positive integers, and , such that the value of is minimum possible and ...
" -v verbose mode. Prints a summary of each packet\n", DEFAULT_TRANSMIT_INTERVAL_USEC); printf( "usage: lcm_source [OPTIONS]\n" "\n" "periodically transmits LC messages.\n" "\n" " -h prints this help text and exits\n" " -m s transmits messages on channel s (otherwise random...
Please control feedback current of each string individually to compensate the current variation among the strings of LEDs. When you design or order the LED driver, please make sure unwanted lighting caused by the mismatch of the LED and the LED driver (no lighting, flicker, etc) never occurs...
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GCD and LCM Problem Description Given two positive integers G and L, could you tell me how many solutions of (x, y, z) there are, satisfying that gcd(x, y, z) = G and lcm(x, y, z) = L? Note, gcd(x, y, z) means the greatest common divisor of x, y and z, while lcm...
function check_path_perm_sanity { # Ensure no element of the path has 0700 permissions, which is very # likely to cause issues for daemons. Inspired by default 0700 # homedir permissions on RHEL and common practice of making DEST in # the stack user's homedir.local...