Step 1:Find the smallest prime number that is a factor of at least one of the numbers, 40, 50, and 60. Write thisprime number(2) on the left of the given numbers(40, 50, and 60), separated as per the ladder arrangement. Step 2:If any of the given numbers (40, 50, 60) is ...
LCM of 40 and 60 is the smallest number among all common multiples of 40 and 60. The methods to find the LCM of 40, 60 are explained here in detail.
给你一个n,要求给出两个整数a和b,使得a+b=n且lcm(a,b)最小。 思路 结论:答案是k和n-k,k为n的最大真因子。 证明:假设a<=b,则lcm>=b,取最小则自然是lcm==b,lcm>b,最小的就是2b,2b>n故舍去,所以我们要构造lcm=b的解。 lcm=b故a整除b,则b=ma,所以a+ma=n,故a整除n。现在lcm=b,a是n...
42=2 ×3 × 7 6 ×7 OR 60=2^2*3*5 OR 6 ×2 ×5 (2 of )2 42 60 66 66=2 × 3 × 11 6 × 11 3 21 30 33 OR 2 correct Factor Trees 7 10 11M1 Implied by correct answer Allow if they thenfind HCF in error 反馈...
百度试题 结果1 题目13. Find the least common multiple (LCM) of 28 and 63.252 相关知识点: 试题来源: 解析 25228 八只 214 3只 0 3x3×7 Lam:2d2xix3 2x2×7 3×3x7 =252 2 ⑦ 3 2 0 3 反馈 收藏
2/4 is not in simplest form since the numerator and the denominator can both be divided by 2. If you get the answer 2/4 to a problem, you should state it in simplest form, 1/2. The process of changing 2/4 to 1/2 is called simplifying the fraction....
给你一个n,要求给出两个整数a和b,使得a+b=n且lcm(a,b)最小。 思路 结论:答案是k和n-k,k为n的最大真因子。 证明:假设a<=b,则lcm>=b,取最小则自然是lcm==b,lcm>b,最小的就是2b,2b>n故舍去,所以我们要构造lcm=b的解。 lcm=b故a整除b,则b=ma,所以a+ma=n,故a整除n。现在lcm=b,a是...
LCM of 40 and 56 is the smallest number among all common multiples of 40 and 56. The methods to find the LCM of 40, 56 are explained here in detail.
14. 两个数的最大公因数和最小公倍数的乘积为 14. The product of the HCF and LCM of two numbers is384。若这两个数
百度试题 结果1 题目14. Find the least common multiple (LCM) of 36 and 54.108(2) 相关知识点: 试题来源: 解析 108EXEXEXZ ⑤ 9 反馈 收藏