百度试题 结果1 题目12. (a)Find the Lowest Common Multiple (LCM) of 24 and 36 相关知识点: 试题来源: 解析 144 反馈 收藏
百度试题 结果1 题目13. Find the least common multiple (LCM) of 28 and 63.252 相关知识点: 试题来源: 解析 25228 八只 214 3只 0 3x3×7 Lam:2d2xix3 2x2×7 3×3x7 =252 2 ⑦ 3 2 0 3 反馈 收藏
相关知识点: 试题来源: 解析 120M1 for finding a correct product of prime factorsor correctly listing a minimum of 3 multiples of 20and 24or for answer 23× 3 x 5 oe or 120k where k is aninteger > 1 反馈 收藏
【题目】Find the LCM of the following numbers:(1)9 and 4(2)12 and 5(3)6 and 5(4)15 and 4(5)Observe a common property in the obtainedLCMs. Is LCM the product of two numbers in each case? 相关知识点: 试题来源: 解析 【解析】(1)Solutions:LCM of 9, 4LCM=2*2*3=36 (2)L...
51. What is the LCM of 12 and 20? 120 80 60 100 Answer The correct answer is:C) 60 Explanation The explanation is: The prime factors of 12 are 22and 3 (since 12 = 2 * 2 * 3). The prime factors of 20 are 22and 5(since 20 = 2 * 2 * 5). ...
【题目】23) Find the LCM of 9 and 12.24) Find the HCF of 16 and 28.25) Write the product in the boxes. 相关知识点: 试题来源: 解析 【解析】 Icmof 9,12 HCFof 16.2 319.121 4116.281 3.4 4.7 ∴2cm=3*3*4 -HCF 141 =136 反馈 收藏 ...
Step 1: The least common multiple is the smallest whole number which is a multiple of each of two or more numbers.Step 2: List the multiples of each number. Find the smallest number that appears in every list.Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40...Multiples ...
LCM of 4 and 18 is the smallest number among all common multiples of 4 and 18. The methods to find the LCM of 4, 18 are explained here in detail.
Updated:9/16/2023 Wiki User ∙8yago Best Answer The LCM is:175 175 Their product. Wiki User ∙8yago This answer is: 👍👎 Add a Comment Add your answer: Earn +20pts Q:What is the set of LCM of 7 and 25? Write your answer... ...
【解析】a)Determine the prime factorization of eachnumber. In Erample 5, we determined that315=32.5.7and 450=2.32.52b)List each prime factor with the greatest exponent that appears in either of the prime factorizations: 2, 3^2 , 5^2 , 7.c)Determine the product of the factors fromStep...