Step 1:Find the smallest prime number that is a factor of at least one of the numbers, 9, 12, and 15. Write thisprime number(2) on the left of the given numbers(9, 12, and 15), separated as per the ladder arrangement. Step 2:If any of the given numbers (9, 12, 15) is a...
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3.Using the Relationship between LCM and GCD (Greatest Common Divisor): Formula: LCM(a, b) = (a * b) / GCD(a, b) For instance, to find the LCM of 12 and 15: Prime factors of 12: 2 x 2 x 3 Prime factors of 15: 3 x 5 ...
LCM of 12 and 21 is the smallest number among all common multiples of 12 and 21. The methods to find the LCM of 12, 21 are explained here in detail.
Example: Consider this as an example; the LCM of \(12\) and \(15\) is \(60\).To find the LCM of numbers, first, you need to mention the multiples of each given number.Thus, the multiples of \(12=12, 24, 36, 48, 60, 72, 84…\) etc.,...
结果1 题目10 Find the lowest common multiple (LCM) of 12 and 16.48..[2] 相关知识点: 试题来源: 解析 48B1$$ f o r 2 ^ { 4 } $$’×3 oe or any other correct multiple or M1 for 12,24,36... and 16,32,48... 反馈 收藏 ...
LCM of 3 and 721 LCM of 9 and 1236 LCM of 8 and 756 LCM of 3 and 824 LCM of 9 and 618 LCM of 12 and 824 LCM of 3 and 99 LCM of 8 and 3232 LCM of 24 and 3672 LCM of 22 and 36396 LCM of 36 and 27108 LCM of 21 and 6363 ...
The LCM is the smallest multiple of numbers that each one can make when you multiply it. It’s like counting by the same number: if you pick 5, you’d then list the whole multiples of 5, 10, 15, 25, 35, and so on. If you also pick 6, you have 6, 12, 18, 24 and 30. ...
Related Least Common Multiples of 3 LCM of 3 and 7 LCM of 3 and 8 LCM of 3 and 9 LCM of 3 and 10 LCM of 3 and 11 LCM of 3 and 12 LCM of 3 and 13 LCM of 3 and 14 LCM of 3 and 15 LCM of 3 and 16 LCM of 3 and 17 LCM of 3 and 18 LCM of 3 and 19 LCM of ...
c) Determine the product of the factors from Step (b) $$ 2 \cdot 3 ^ { 2 } \cdot 5 ^ { 2 } \cdot 7 = 2 \cdot 9 \cdot 2 5 \cdot 7 = 3 1 5 0 $$ T hus, 3150 is the least common multiple of 315 and 450. It is the smallest natural number that is evenly divisible...