line 连接线成矩形(也可以通过rectangle命令来实现) 对于矩形来说,我们还有更加简化的代码,我们可以通过命令 Rectangle(关键词)来实现。一般在绘制矩形时我们会确定两个坐标(左下和右上);对角线上两端点的坐标。并且可以通对角线上的坐标来改变矩形的形状。 \begin{tikzpicture} \draw (0,0) rectangle (4,4);...
\hline % draw a line name &1&2&3 \\ \hline peter &2&3&4 \\ \hline \end{tabular} test for a table \begin{table}[ht] \begin{center} % center for caption?? \begin{tabular}{l|r|r|r} \hline % draw a line Name &1&2&3 \\ \hline Peter &2&3&4 \\ \hline \end{t...
\tkzDrawLine(A,C) \tkzDrawCircle[circum](A,B,C) \tkzDrawCircle[in](A,B,C) \tkzDrawCircle(C,A) \tkzDrawCircle[red,dashed,thick,R](C, 2cm) 效果图 好像还不错? 1.4 获取生成的点及线段长度 以上,最基本的画图就告一段落了～ 可是,如果我们想要两个几何对象相交,获取交点;或者是获取一个圆...
{scope} % angle gamma \begin{scope}[shift={(60:4)}] \draw[fill=green!30] (0,0) -- (-120:.75cm) arc (-120:-60:.75cm); \draw (-90:0.5cm) node {$\gamma$}; \end{scope} % the triangle \draw [line width=1.5pt] (A) -- (B) -- (C) -- cycle; \end{tikzpicture}...
{draw=black,line width=2pt,{Latex[length=2mm,width=2.5mm]}-{Latex[length=2mm,width=2.5mm]},},arrow4/.style={draw=black,dashed,line width=1pt,-{Latex[length=2mm,width=2.5mm]},}]\node(n1)[box,label={[lbl]north west:Challenger~~$\mathcal{C}$}]{$ \begin{aligned}\\(vk,sk)\...
您不需要定义新的坐标，但可以使用calc库中的投影标识符。
\draw[blue] (2,1)|-(1,2);%直角2 \draw[green] (2,2) circle (1);%圆:圆心、半径 \draw[black] (4,4) ellipse (1 and 3);%椭圆:短、长半轴 \draw[yellow] (3,3) rectangle (4,1);%矩形 \draw[orange] (0,0) -- (2,1-|1,2);%找到垂点并与(0,0)连线 ...
\draw[green] (2,2) circle (1);%圆:圆心、半径 \draw[black] (4,4) ellipse (1 and 3);%椭圆:短、长半轴 \draw[yellow] (3,3) rectangle (4,1);%矩形 \draw[orange] (0,0) -- (2,1-|1,2);%找到垂点并与(0,0)连线
\draw[domain=-1:1] plot(\x,{\x*\x*2-1}); \end{tikzpicture}%%%%%%%%%%%%%% %%%%%%%%%%%%%%\begin{tikzpicture}[thick] \draw[blue] (0,0) rectangle (1,1); \filldraw[fill=yellow,draw=red] (2,0.5) circle [radius=0.5]; ...
Inside the environment there are two\drawcommands. They mean: The path, which is specified following the command up to the semicolon, should be drawn.” The first path is specified as (-1.5,0) --(0,1.5), which means “a straight line from the point at position (−1.5, 0...