CURRENT_DATE - (EXTRACT(DAY FROM CURRENT_DATE) - 1) - INTERVAL '1' MONTH AND CURRENT_DATE - EXTRACT(DAY FROM CURRENT_DATE) ORDER BY ELAPSED_TIME DESC 请注意,这个查询不是标准的,我故意使用Oracle风格的日期算法来简化查询,它是H2支持的。ADD_MONTH如果您愿意,也可以在此处使用非标准。 如果您只需...
The OracleLAST_DAY()function always returns aDATEvalue that represents the last day of the month of that input date. Examples Let’s look at the following examples of using theLAST_DAY()function. A) Get the last day of the current month ...
ADD_MONTHS CURRENT_DATE CURRENT_TIMESTAMP DBTIMEZONE EXTRACT(datetime) FROM_TZ LAST_DAY LOCALTIMESTAMP MONTHS_BETWEEN NEXT_DAY NUMTODSINTERVAL NUMTOYMINTERVAL ROUND (date) SESSIONTIMEZONE SYS_EXTRACT_UTC SYSDATE SYSTIMESTAMP TO_CHAR (datetime) TO_DSINTERVAL TO_TIMESTAMP TO_TIMESTAMP_TZ TO_YMINT...
SELECT SYSDATE, LAST_DAY(SYSDATE) "Last", LAST_DAY(SYSDATE) - SYSDATE "Days Left" FROM DUAL; SYSDATE Last Days Left --- --- --- 30-MAY-09 31-MAY-09 1 The following example adds5months to the hire date of each employee to give an evaluation date: Copy SELECT last_name, hire_...
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In any case, the current Date functions accept astarting_onparameter on itsday_of_weekfunctions and "monday" will return a different number depending if it starts on a monday or a sunday. Wouldn't it be better to keep equivalence with that behaviour then?https://hexdocs.pm/elixir/main/Da...
In the general case, to find the first of the month for any monthnmonths away from a given date, calculate the first of the month for the date, and then shift the result bynmonths: DATE_ADD(DATE_SUB(d,INTERVAL ... GetMySQL Cookbook, 2nd Editionnow with the O’Reillylearning platform...
SELECT DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0) Stick to that pattern, don't corrupt it with -1 tricks! That just makes it more confusing later. If you need the last day of the current month, then (1) add a month and then (2) subtract a day. Do this directly, not ...
Add and subtract months to a date without exceeding the last day of the new month
import subMonths from "date-fns/subMonths"; import addMonths from "date-fns/addMonths"; const startDate = new Date(2023, 2, 28); const oneMonthAhead = addMonths(startDate, 1); const result = subMonths(oneMonthAhead, 1); console.log(result); // prints 28th of February 👀 7 ...