sum(hp.planned_payment_amount) AS planned_payment_amount_sum, CONCAT(DATE_FORMAT(hp.planned_payment_date, '%Y-%m'), '-01') AS planned_payment_date, hp.pay_in_or_out FROM byjz_fin_all.hlfn_project_position hp LEFT JOIN byjz_bus.hlpj_project bp ON hp.PROJECT_ID = bp.PROJECT_ID ...
语法 last_day(expr) 参数 expr:一个DATE表达式。 返回 一个DATE。 示例 SQL >SELECTlast_day('2009-01-12'); 2009-01-31 >SELECTlast_day('2009-02-12'); 2009-02-28 相关函数 next_day 函数 反馈 此页面是否有帮助? 是否 提供产品反馈
首先,让我们解释一下这个问答内容中的两个名词。 1. Function(函数):函数是一段可重复使用的代码,它接受输入,经过处理后产生输出。在编程中,函数有助于提高代码的可读性、可维护性和可扩展...
預設範圍為RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW。 在此範例中,使用該預設範圍 (或不包含範圍而使用預設值) 會導致DifferenceFromLastQuarter資料行中傳回零。 如需詳細資訊,請參閱OVER 子句 (Transact-SQL)。 SQL USEAdventureWorks2022; GOSELECTBusinessEntityID,DATEPART(QUARTER, QuotaDate)ASQuarter,...
-- * IN ORDER TO USE THE DATE FUNCTION, THE DATA MUST HAVE A -- * RECOGNIZABLE DATE FORMAT. HERE WE CREATE YYYY-MM-DD BY ADDING -- * THE '-' INTO THE VALUE AFTER CAPTURING A SUBSTRING FOR THE -- * YEAR, MONTH, AND DAY. ...
默认范围为RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW。 在此示例中,使用默认范围(或不包括范围,导致使用默认范围)将导致在DifferenceFromLastQuarter列中返回零。 有关详细信息,请参阅OVER 子句 (Transact-SQL)。 SQL USEAdventureWorks2022; GOSELECTBusinessEntityID,DATEPART(QUARTER, QuotaDate)ASQuarter,YEAR...
EN如何分别获取当前日期的年月日以及在一年中的第几天 import time localtime = time.localtime(time...
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contains the data you want to use or an expression that performs a calculation using the data in that field. Operands inexprcan include the name of a table field, a constant, or a function (which can be either intrinsic or user-defined but not one of the other SQL aggregate functions)....
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