class Solution: # @param num, a list of integers # @return a string def largestNumber(self, num): def compare(num1, num2): if len(num1) != len(num2): num1,num2 = num1 + num2,num2 + num1 return [-1, 1][num1 > num2] d = {} for n in num: n = str(n) if n ...
# @return a string def largestNumber(self, num): def compare(num1, num2): if len(num1) != len(num2): num1,num2 = num1 + num2,num2 + num1 return [-1, 1][num1 > num2] d = {} for n in num: n = str(n) if n not in d: d[n] = 1 else: d[n] = d[n] +...
def largestNumber(self, num): comp=lambda a,b:1 if a+b>b+a else -1 if a+b<b+a else 0 num=map(str,num) num.sort(cmp=comp,reverse=True) return str(int("".join(num))) 但是python3已经删除了cmp参数,所以取而代之的用法: def cmp_to_key(mycmp): 'Convert a cmp= function into...
得注意记录改变状态有三种class Solution: def maximumNumber(self, num: str, change: List[int]) -> str: changed = 0 num_list = list(num) for i, v in enumerate(num_list): if changed == 2: break o = n…
class LargerNumKey(str): def __lt__(x, y): return x+y > y+x class Solution(object): def largestNumber(self, nums): """ :type nums: List[int] :rtype: str """ nums = "".join(sorted([str(item) for item in nums],key=LargerNumKey)) return "0" if nums[0]=="0" else...
这是一个使用Python编写的LeetCode题目解,题目编号为179。题目要求实现一个函数,输入一个整数数组nums和一个目标值target,返回数组中最大的数。 代码如下: def largest_number(nums, target): max_num = float('-inf') for num in nums: if num > max_num and num > target: ...
value=int(num)except:print("Invalid input")continueiflargestisNoneorsmallestisNone: largest=value smallest=valueelifsmallest >value: smallest=valueeliflargest <value: largest=valueprint("Maximum is", largest)print("Minimum is", smallest) 用到的知识点: ...
Return the larger of the two input numbers. For example, with inputs num1 = 3 and num2 = 7, the return value should be 7. 1 2 3 int max_of_two(int num1, int num2) { } Check Code Share on: Did you find this article helpful?Our...
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Python solutionclass Solution: def dominantIndex(self, nums): """ :type nums: List[int] :rtype: int """ if len(nums) == 1: return 0 largest, second_largest, k = 0, 0, 0 for i, num in enumerate(nums): if num > largest: second_largest, largest, k = largest, num, i elif...