public class Solution { public String largestNumber(int[] nums) { Integer[] ints = new Integer[nums.length]; // 将其放入Integer数组方便排序 for(int i = 0; i < nums.length; i++){ ints[i] = nums[i]; } // 排序的方法是前后相拼再后前相
public String largestNumber(int[] nums) { if(nums==null || nums.length==0) return ""; int n = nums.length; Integer[] arr = new Integer[n]; for(int i=0; i<n; i++){ arr[i] = nums[i]; } Arrays.sort(arr, new Comparator<Integer>(){ public int compare(Integer o1, Integer...
}elseif((int) num1_copy % 10 < (int) num2_copy % 10){return-1; }else{intflag = (int) num1_copy % 10;while((int) num1_copy % 10 == (int) num2_copy % 10 && (int) num1_copy != 0 && (int) num2_copy != 0){ flag= (int) num1_copy % 10; num1_copy= num1_c...
先把int数组转为String,然后做一个比较器,这里有一个小技巧可以用 (o2 + o1).compareTo(o1 + o2)作为比较器,可以将"大数字"放到前面,然后按照比较器的顺序输出即可,JAVA实现如下: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 publicString largestNumber(int[] nums) { String[] str=newStrin...
(i,i+1));}// Sorting the array in ascending orderArrays.sort(num);// Initializing variables to calculate the smallest and largest integersinta=0;intb=0;intc=1;// Calculating the smallest and largest integers from the sorted arrayfor(inti=0;i<8;i++){a+=num[i]*c;b+=num[7-i]*...
import java.util.*; public class LargestNumber{ public static void main(String[] args){ int[] num = {3232543,0,0,34350,34,12312329,86,5}; System.out.println("结果:" + getLargestNumber(num)); } private static String getLargestNumber(int[] num){ ...
Java Code: // Import the necessary Java classes.importjava.util.*;// Define the 'solution' class.publicclasssolution{// Define a method to find the largest number using an array of numbers.publicstaticStringlargest_Numbers(int[]num){// Convert the array of numbers to an array of strings....
javapublic class Solution { public String largestNumber(int[] num) { int length = num.length; String[] numStr = new String[length]; for (int i = 0; i < length; i++) { numStr[i] = String.valueOf(num[i]); } Arrays.sort(numStr, new StringComparator()); ...
cmp_to_key(cmp), reverse=True) return str(int(''.join(nums_str))) Reference https://leetcode.com/problems/largest-number/ 本文参与 腾讯云自媒体同步曝光计划,分享自作者个人站点/博客。 原始发表:2021/02/01 ,如有侵权请联系 cloudcommunity@tencent.com 删除 前往查看 sdn com version 博客 函数...
Java版本: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classPimplementsComparable<P>{int idx;int val;P(int idx,int val){this.idx=idx;this.val=val;}@OverridepublicintcompareTo(Pthat){returnthat.val-this.val;}}publicintdominantIndex(int[]nums){int n=nums.length;if(n==1)return-1...