Difference Between Largest and Smallest Integer Write a Java program to find the difference between the largest integer and the smallest integer. These integers are created by 8 numbers from 0 to 9. The number
importjava.util.Scanner;publicclassSolution{publicstaticvoidmain(String[]args){// Initializing an integer variable 'n' with the value 2350intn=2350;// Displaying the original numberSystem.out.printf("Original Number: %d\n",n);// Initializing a variable to count the number of right shiftsintsh...
因此,在选择右边界的时候,首先找到一个height[k] < height[k - 1]的k,然后取k - 1作为右边界,穷举所有左边界,找最大面积。 java代码: //O(n^2) with pruningpublicintlargestRectangleArea1(int[] height) {//Start typing your Java solution below//DO NOT write main() functionintarea = 0;for(...
intcurrArea = (i - j) * heightStack.pop(); if(currArea > area) { area = currArea; } } heightStack.push(height[i]); indexStack.push(j); } } while(!heightStack.empty()) { intcurrArea = (height.length - indexStack.pop()) * heightStack.pop(); if(currArea > area) { area...
integer number among three using conditional operator * @author includehelp */ public class LargestNumber { /** * Method to find largest number using conditional operator * @param a * @param b * @param c * @return */ static int getLargest(int a,int b,int c){ int largeest ...
importjava.util.Scanner; publicclassFinder { publicstaticvoidmain(Stringargs[]) { intlrg,size,i; intnumArr[]=newint[50]; Scannerscan=newScanner(System.in); System.out.print("Enter Array Size : "); size=scan.nextInt(); System.out.print("Enter Array Elements : "); ...
arpit.java2blog.generic; public class FindSecondLargestMain { public static void main(String args[]) { int[] arr1={7,5,6,1,4,2}; int secondHighest=findSecondLargestNumberInTheArray(arr1); System.out.println("Second largest element in the array : "+ secondHighest); } public static ...
classSolution {publicintlargestRectangleArea(int[] heights) { Stack<Integer> st =newStack<Integer>();if(heights.length == 0)return0;intleftIndex;inttopIndex;intarea;intmaxArea = 0;inti = 0;while(i <heights.length){if(st.empty() || heights[i] >=heights[st.peek()]){ ...
我们直接使用 java 提供的排序算法,又因为默认是从小到大排序,所以将倒数第 k 个数返回即可。 public int findKthLargest(int[] nums, int k) { Arrays.sort(nums); return nums[nums.length - k]; } 解法二 我们没必要把所有数字正确排序,我们可以借鉴快排中分区的思想,这里不细讲了,大家可以去回顾一下快...
import java.util.Map; public class LargestTimeForGivenDigits { public static void main(String[] args) { int[] nums = {1, 2, 3, 4}; System.out.println(largestTimeForGivenDigits(nums)); } public static Map largestTimeForGivenDigits(int[] nums) { Map result = new HashMap(); for (int...