set to -1 initially). Traverse the array, starting from the second item in the array, letliistore the largest item's index,sliistore the second largest one's. It can complete inO(n).
k:int)->int:# 将问题转化为寻找第n-k个最小元素k=len(nums)-kdefquickSelect(l,r):pivot,p=nums[r],l# 将小于等于pivot的元素移动到左侧foriinrange(l,r):ifnums[i]<=pivot:nums[p],nums[i]=nums[i],nums[p]p+=1# 将pivot放到正确的位置上nums[p],nums[r]=nums[r],nums[p]# 如果p...
To find the largest element from the array, a simple way is to arrange the elements in ascending order. After sorting, the first element will represent the smallest element, the next element will be the second smallest, and going on, the last element will be the largest element of the arr...
我们直接使用 java 提供的排序算法,又因为默认是从小到大排序,所以将倒数第 k 个数返回即可。 public int findKthLargest(int[] nums, int k) { Arrays.sort(nums); return nums[nums.length - k]; } 解法二 我们没必要把所有数字正确排序,我们可以借鉴快排中分区的思想,这里不细讲了,大家可以去回顾一下快...
链接:http://leetcode.com/problems/kth-largest-element-in-an-array/ 题解: 找数组中第k大的元素,可以用heap,Radix sort或者Quick-Select。不过Quick-Select的Time Compleixty只有在Amorized analysis上才是O(n)。下面是使用Java自带的priority queue min-heap来完成的,算是投机取巧了。二刷要补上Radix sort以...
215. Kth Largest Element in an Array** https://leetcode.com/problems/kth-largest-element-in-an-array/description/ 题目描述 Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, ...
215. Kth Largest Element in an Array Find K-th largest element in an array. Notice You can swap elements in the array Example In array[9,3,2,4,8], the 3rd largest element is4. In array[1,2,3,4,5], the 1st largest element is5, 2nd largest element is4, 3rd largest element is...
https://leetcode.com/problems/kth-largest-element-in-an-array/description/ 内置排序beat 99%,重新写一下归并和快排比比试试。 自己写的归并排序,beat 40% . 快速排序由于基准点问题第一次直接 TLE. 好吧,修改一下,选取基准点的方法基本是: 1. 取左端或右端。 2. 随机取。 3. 取...
Getting the n largest values of an array using NumPyTo get the n largest values of an array using NumPy, you can simply use we will use np.argpartition(arr, -n)[-n:]. This method is used to perform an indirect partition along the given axis using the algorithm specified by the kind...
second_largest_values = nums[indices, np.arange(nums.shape[1])]: This line creates a new array second_largest_values by indexing nums using the row indices in indices and column indices created by np.arange(nums.shape[1]), which returns an array of integers from 0 to the number of col...