1.Problem Find thekth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. 题意很简单,找到一个一维数组中的第K大的数并返回。数组中第K大的数也是面试中经常考察的问题。现在就借Leetcode上的这题来详细总结下这个问题的...
所以这道题的思路就是,先partition一次,然后如果正好是第k-1个,那就返回,不然如果partition完左侧加起来的数字数目已经超过了k-1,那么说明右侧反正都小于这个pivot了,就只对左侧递归,不然就对右侧递归 1publicintfindKthLargest(int[] nums,intk) {2if(nums.length == 1) {3returnnums[0];4}5intidx = -...
我们直接使用 java 提供的排序算法,又因为默认是从小到大排序,所以将倒数第 k 个数返回即可。 public int findKthLargest(int[] nums, int k) { Arrays.sort(nums); return nums[nums.length - k]; } 解法二 我们没必要把所有数字正确排序,我们可以借鉴快排中分区的思想,这里不细讲了,大家可以去回顾一下快...
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given [3,2,1,5,6,4] Note: You may assume k is always valid, 1 ≤ k ≤ array's length. Credits: Special tha...
215. Kth Largest Element in an Array 题目大意:给定无序数组求第k大,经典面试题 题目思路:利用快速排序,每次定一个轴,比轴大的放左边,小的放右边,如果左边的数量小于k,则第k大在右边,反之在左边,每次去找就好了 时间复杂度&&空间复杂度:O(n)(需要找的总共次数为n/2+n/4+…+1 = 2n-1...
Write a Scala program to compute the average value of an array element except the largest and smallest values. Sample Solution: Scala Code: objectscala_basic{defmain(args:Array[String]):Unit={vararray_nums=Array(5,7,2,4,9);println("Original array:")for(x<-array_nums){print(s"${x},...
The disk drive provides a method of adaptively managing a cache segment divided into chunks by defining an unavailable data type to be stored in an element of a chunk array which indicates that the chunk is not available, and defining an available data type to be stored in an element of ...
第k大的数 = 第len-k+1小的数 len=end+1 然后实际是找第k-1索引处的数 , 因此为end+1-k+1-1 (其实这里的定义有点混乱了 , 不管怎样第一次Accepted了 , 之后再改进 ) LeetCode Kth Largest Element in an Array 结果 funcpartition(nums[]int,startint,endint)int{p:=start ...
2.选择排序 从list中比较所有的选择最大的和最后一个元素交换,重复此动作。 classSolution:deffindKthLargest(self,nums,k):""" :type nums: List[int] :type k: int :rtype: int """foriinrange(k):temp=0forjinrange(len(nums)-i):ifnums[j]>nums[temp]:temp=j ...
\n"); // input array elements for (int i = 0; i < n; i++) scanf("%d", &a[i]); // recursive function to find the maximum of the array int big = findBigRec(a, n); printf("The biggest element in the array is: %d\n", big); return 0; } ...