/* * @lc app=leetcode id=215 lang=cpp * * [215] Kth Largest Element in an Array */ // @lc code=start class Solution { public: int findKthLargest(vector<int>& nums, int k) { const auto partition = [&](int l, int r) { const int ind = rand() % (r - l + 1) + l...
215. Kth Largest Element in an Array Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given [3,2,1,5,6,4] and k = 2, return 5. Note: You may assume k is always valid, ...
/** * @param n: An integer * @param nums: An array * @return: the Kth largest element */ int kthLargestElement(int k, vector<int> &nums) { int n = nums.size(); // 为了方便编写代码,这里将第 k 大转换成第 k 小问题。
215 Kth Largest Element in an Array # 215 Kth Largest Element in an Array 题目来源: https://leetcode.com/problems/kth-largest-element-in-an-array/description/ 题意分析: 在一个无序链表中找出第k大的元素。 Example 1: Input: [3,2,1,5,6,4] and k = 2 Outp......
class Solution: # @param nums {int[]} an integer unsorted array # @param k {int} an integer from 1 to n # @return {int} the kth largest element def kthLargestElement2(self, nums, k): # Write your code here import heapq heap = [] for num in nums: heapq.heappush(heap, num)...
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static int findSumMax(std::vector<int>& num, int x) { int curr = num[0]; int element = 0; int elementnew; int i; for(i = 1; i<x; i++) { elementnew = (curr > element) ? curr : element; curr = element + num[i]; element = elementnew; } return ((curr > element) ...
In a given integer arraynums, there is always exactly one largest element. Find whether the largest element in the array is at least twice as much as every other number in the array. If it is, return the index of the largest element, otherwise return -1. ...
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Edit & run on cpp.sh Then assign those digits to an array of some sort or a container then check the largest/smallest digits manually or using the std::min_element and std::max_element. Sep 25, 2013 at 1:12am kokojin(3) is assigning the digits to an array the only way to do ...