你也可以试试这个（只有当query返回你想要的name时，它才会获取记录，否则没有）：
你也可以试试这个（只有当query返回你想要的name时，它才会获取记录，否则没有）：
/** creates a subquery to get the status of the last inserted related "tracking" */ $q->select('status') ->from('tracking') ->whereColumn('order_id', 'orders.id') ->where('created_at', function ($q) { /** a subquery to get the latest inserted tracking record (only the last ...
In cases where you don't want the sort to be part of the relationship definition as in the accepted answer, you can also pass an array to the Eloquent::with() method. The key indicates the relationship name, and the value is a function that is passed the Builder object: $sortDirection...
In other words, Eloquent will look for the value of the user's id column in the user_id column of the Phone record. If you would like the relationship to use a value other than id, you may pass a third argument to the hasOne method specifying your custom key:return $this->hasOne(...
另外,上面也已经提到由于relationship本身就是query builder因此可以增加约束级联,比如: Post::find(1)->comments()->where('title','foo')->first()就只取title为foo的第一条post对应的comment other_local_postid_key就是 注意按照laravel默认命名规约,一对多的关系模型,child model中的owning model ...
Where 是一个约束声明，使用Where约束来自数据库的数据，Where是在结果返回之前起作用的，Where中不能使用...
// #1 Using deferred insert $category->appendToNode($parent)->save(); // #2 Using parent category $parent->appendNode($category); // #3 Using parent's children relationship $parent->children()->create($attributes); // #5 Using category's parent relationship $category->parent()->...
return $this->belongsToMany('App\Role')->wherePivot('approved', 1); return $this->belongsToMany('App\Role')->wherePivotIn('priority', [1, 2]);远层一对多#「远层一对多」提供了方便简短的方法来通过中间的关联获取远层的关联。例如,一个 Country 模型可能通过中间的 Users 模型关联到多个 Posts...
接下来就是怎么使用的问题了。 Route::get('model/test/relationship',function() { $id=(int)request()->get('id',0); $info=\App\Models\MTest::find($id); dump($info); dump