0 How to apply condition to Laravel eloquent relation -1 Laravel Eloquent A good way to make relationship between country state and city table Related 6 Laravel 4 hasMany with WHERE clause 2 Laravel query with hasmany relationship 0 Getting to use Eloquent hasMany() relationship 2 Get...
Relationship with conditions and ordering public function orders() { return $this->hasMany('App\Order'); } 其实我们可以在获取多订单的同时,加入筛选语句和排序。如,获取已支付并按更新时间倒序输出: public function paidOrders() { return $this->hasMany('App\Order')->where('paid', 1)->orderBy(...
By default, Laravel will determine the relationship associated with the given model based on the class name of the model; however, you may specify the relationship name manually by providing it as the second argument to the whereBelongsTo method:...
When I am combining whereBelongsTo with OR condition using the orWhere(), the data set returns blank. But if simply write $query->whereBelongsTo($membershipCenters, 'employeeMembershipCenter'); It works as it intends to. What am I doing wrong? laravel relationship Share Improve this questio...
如果該列具有相同的值,則只查詢一次記錄並獲取第一條記錄 (Querying the record just once and taking the first record if the column has same value) Laravel Eloquent 使用嵌套關係構建 eloquent 集合 (Laravel Eloquent use nested relationship to construct eloquent collection)留言...
To perform this action, it is necessary to establish a relationship between the User model and the Account model. By doing so, you will be able to access the Account associated with a particular User. Solution 3: This solution requires you to implement it in the following manner. Solution ...
我认为这是正确的方法:
Controller Code: Read Also:Laravel Check If Relationship Data is Empty Example <?php namespaceApp\Http\Controllers; useIlluminate\Http\Request; useApp\Models\User; classUserControllerextendsController { /** * Write code on Method * * @return response() ...
我需要按作用域记录用户通知,但它返回App\User::notifications must return a relationship instance.。代码 layout @auth @if(auth::user()->notifications > 0)
因为第一个查询总是返回相同的结果,所以我宁愿不运行两次。 SET @sid = (SELECT status_id FROM user_relationship_status WHERE status = 'LIKE'); INSERT INTO user_relationships (user_id, target_user_id, 浏览3提问于2016-03-27得票数 1 回答已采纳...