work.cpp: In lambda function: work.cpp:15:24: error:'this'was not capturedforthislambda function []() { cout<<val << endl; }();^~~work.cpp:15:24: error: invalid use of non-staticdata member'C::val'work.cpp:10:9:
在这里推荐一个工具cppinsights,是一款C++源代码到源代码的转换,它可以把C++中的模板、auto以及C++11新特性展开。通过使用cppinsights,我们可以清楚地看到编译器做了哪些事情。 值捕获 仍然使用前面的代码,如下: int main() { int x = 5; auto fun = [x]() { printf("%d\n", x); }; fun(); return ...
int value = 10; // returns an error - value is a const inside the expression auto decrement = [ value ]( ){ return --value; }; auto increment = [ value ]( ) mutable { return ++value; }; increment; // 11 尽管其他选项很少使用,但您可以在 cppreference.com 的 lambdas 页面上获得有...
对lambda表达式用法进行总结, 参考:1.https://docs.microsoft.com/en-us/cpp/cpp/lambda-expression-syntax?view=vs-2019 2.《深入理解C++11》 lambda函数在C++11标准中默认是内联的,类似于其他语言中的局部函数(local function),或内嵌函数(nested function)。 lambda lambda表达式与普通函数最大的区别之一是:lambd...
// function_lambda_expression.cpp // compile with: /EHsc /W4 #include <algorithm> #include <iostream> #include <vector> using namespace std; class Scale { public: // The constructor. explicit Scale(int scale) : _scale(scale) {} // Prints the product of each element in a vector obj...
// throw_lambda_expression.cpp // compile with: /W4 /EHsc int main() // C4297 expected { []() noexcept { throw 5; }(); } 有关详细信息,请参阅异常规范 (throw)。返回类型将自动推导 Lambda 表达式的返回类型。 无需使用 auto 关键字,除非指定了 trailing-return-type。 trailing-return-type...
cb.cpp:Infunction ‘int main()’:cb.cpp:23:30:error:cannot convert ‘main()::<lambda(void*)>’ to ‘void*(*)(void*)’23|pthread_create(&t,NULL,cb,NULL);|^~|||main()::<lambda(void*)>Infile includedfrom/usr/include/x86_64-linux-gnu/c++/9/bits/gthr-default.h:35,from/usr/...
// captures_lambda_expression.cpp// compile with: /W4 /EHsc#include<iostream>usingnamespacestd;intmain(){intm =0;intn =0; [&, n] (inta)mutable{ m = ++n + a; }(4);cout<< m <<endl<< n <<endl; } Output 5 0 Because the variablenis captured by value, its value remains0aft...
// captures_lambda_expression.cpp// compile with: /W4 /EHsc#include<iostream>usingnamespacestd;intmain(){intm =0;intn =0; [&, n] (inta)mutable{ m = ++n + a; }(4);cout<< m <<endl<< n <<endl; } Output 5 0 Because the variablenis captured by value, its value remains0aft...
// even_lambda.cpp // compile with: cl /EHsc /nologo /W4 /MTd #include <algorithm> #include <iostream> #include <vector> using namespace std; int main() { // Create a vector object that contains 10 elements. vector<int> v; ...