The trivial way, O(m + n): Merge both arrays and the k-th smallest element could be accessed directly. Merging would require extra space of O(m+n). The linear run time is pretty good, but could we improve it even further? A better way, O(k): There is an improvement from the ...
Kth element of Two Sorted Arrays 1publicclassFindKthSorted {2//Method 1: time complexity O(k), no extra space34publicintfindKth (int[] a,int[] b,intk) {5intlenA =a.length;6intlenB =b.length;7if(k > lenA +lenB) {8thrownewRuntimeException("Cannot find");9}10intindexA = lenA...
class Solution{public:intcountLargerOrEqualThanK(vector<int>&nums,intk){autoc=0;for(autox:nums){if(x>=k){c++;}}returnc;}intfindKthLargest(vector<int>&nums,intk){intmax=*max_element(nums.begin(),nums.end());intmin=*min_element(nums.begin(),nums.end());while(min<=max){intmid=m...
The largest element to take from the second array is smaller than the smallest element we do not take from the first array (21 < 27).It’s easy to visualize (d’) why that condition works: all elements we take from the two arrays are surely smaller than any other element in the two...
Find the Kth element from two sorted arrays 这道题的关键是如何建立两个数组的之间的关系。插入排序法和双指针法可以达到线性时间复杂度。这里记录一个更加巧妙的思路,利用二分法达到O(logm + logn)的时间复杂度。 原文地址 https://articles.leetcode.com/find-k-th-smallest-element-in-union-of/...
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given[3,2,1,5,6,4]and k = 2, return 5. [一句话思路]:快速选择:先利用pivot进行两侧的排序,再选一侧递归查找。
Kth Smallest Number in Sorted Matrix Find thekth smallest number in at row and column sorted matrix. Given k =4and a matrix: [ [1 ,5 ,7], [3 ,7 ,8], [4 ,8 ,9], ] return5 这一题是Kth Largest Element in an Array的拓展,主要是在排序数组中我们如何从小到大选择,最终到达第k小...