针对你遇到的 kibana security_exception: missing authentication credentials for rest request 错误,以下是一些可能的解决步骤和原因分析,帮助你解决这个问题: 1. 确认Kibana服务状态及配置 首先,确保Kibana服务正在正常运行。你可以通过检查Kibana服务的状态来确认这一点。在Linux系统上,你可以使用如下命令: bash sudo ...
浏览器访问提示:Kibanaserver is not ready yet.(服务器尚未准备就绪。) 查看kibana日志:missing authentication credentials for REST request… 解决 设置密码 根据日志提示,是因为没有设置elasticsearch的账号密码,所以直接设置为elasticsearch的初始密码 elasticsearch.username: "elastic"elasticsearch.password: "elastic2022...
logs.alert.document.count:270b74f0-f3c2-11ec-9a6e-414bc063a8ba: execution failed - security_exception: [security_exception] Reason: missing authentication credentials for REST request [/_security/user/_has_privileges], caused by: ""
Executing Alert default:.es-query:{uuid} has resulted in Error: security_exception: [security_exception] Reason: missing authentication credentials for REST request [/_security/user/_has_privileges], caused by: "" ...appears a lot and accounts for around 200 rule execution failures per minute....
[ERROR][elasticsearch-service] Unable to retrieve version information from Elasticsearch nodes. security_exception: [security_exception] Reason: missing authentication credentials for REST request [/_nodes?filter_path=nodes.*.version%2Cnodes.*.http.publish_address%2Cnodes.*.ip] 2022-08-27T03:18:39...
"curl -s --cacert config/certs/ca/ca.crt https://localhost:9200 | grep -q 'missing authentication credentials'", ] interval: 10s timeout: 10s retries: 120 kibana: depends_on: elasticsearch: condition: service_healthy image: docker.elastic.co/kibana/kibana:${STACK_VERSION} ...
[ "CMD-SHELL", "curl -s --cacert config/certs/ca/ca.crt https://localhost:9200 | grep -q 'missing authentication credentials'", ] interval: 10s timeout: 10s retries: 120 es03: depends_on: - es02 image: elasticsearch:${STACK_VERSION} volumes: - certs:/usr/share/elasticsearch/config...
Kibana是一个针对Elasticsearch的开源分析及可视化平台，使用Kibana可以查询、查看并与存储在ES索引的数据进行...
1.从目录elasticsearch-8.0.0\bin打开另一个命令提示符，并运行以下命令。注意：我们正在为用户"kibana...
这是一个有点怪物，但有一个原因，你不使用官方的Docker Compose setup-你可以削减它到一个单一的...