(II)解:kn= yn-yn-1 xn-xn-1= 5 Tnan,n=1,2,…,5,因为a1<a2<a3<a4<a5,所以k1<k2<k3<k4<k5.(III)证明:由于f(x)的图象是连接各点Pn(xn,yn)(n=0,1,…,5)的折线,要证明f(x)<x(0<x<1),只需证明f(xn)<xn(n=1,2,3,4).事实上,当x∈(xn-1,xn)时,f(x)= f(xn)-f(xn...