I have made this solution for K-string (Codeforce Round 135 Div.2 Problem A). I have did same as in editorial.. can u please point out any error in this ??? #include<iostream>#include<cstdio>#include<cstring>#include<cstdlib>usingnamespacestd;intmain(){inti,j,k,freq[26],repeat,n...
Input:Four lines: each line consists of a single string. Output:An integer representing the answer. Input:aabb abab baba acba Output:4 The four sequences are "a", "b", "aa", and "ab". Any kind of help would be appreciated. Thanks in advance....
the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
Recall that the string ss of length nn is lexicographically less than string tt of length nn, if there exists such ii (1≤i≤n1≤i≤n), that si<tisi<ti, and for any jj (1≤j<i1≤j<i) sj=tjsj=tj. The lexicographic comparison of strings is implemented by the operator < in mode...
Rearrange the letters in string s in such a way that the result is a k-string. Print the result on a single output line. If there are multiple solutions, print any of them. If the solution doesn't exist, print "-1" (without quotes). Input The first input line contains integer k ...
参考资料:https://codeforces.com/gym/103446/attachments/download/14828/LiyuuCute.pdf#include <bits/stdc++.h> using namespace std; void print(string s, int cnt) { for (int i = 0; i < cnt; i ++ ) cout << s; } void solve() { int n; cin >> n; if (n == 2) cout << "...
原理链接: https://codeforces.com/problemset/problem/1328/B 测试样例: Input 7 5 1 5 2 5 8 5 10 3 1 3 2 20 100 Output aaabb aabab baaba bbaaa abb bab aaaaabaaaaabaaaaaaaa 题意: 给你一个长为 n n n的只由 ( n − 2 ) (n-2) (n−2)个 a a a和 2 2 2个 b b b...
codeforces 1328 B. K-th Beautiful String,题意:就是找到第kkk个全排列的字符串通过找规律,第一个bbb在倒数第二位有111个,倒数第三位222个,倒数第四位三个,第二个bbb的位置就是k−1−2−3−...k-1-2-3-...k−1−2−3−...剩下的数字倒着数。这样位置
If the solution exists, output «YES» (without quotes) in the first line. Then in the second line output a single integerx— the number of the character that should be removed fromsso that the resulting string would be a palindrome. The characters in the string are numbered from 1. ...
, a.size()) == a; } void insert(string s, int id) { int p = 0; for (auto c : s) { int u = get(c); if (!tr[p][u]) tr[p][u] = ++ idx; p = tr[p][u]; pos[p] = id; } } void solve() { cin >> n; for (int i = 0; i < n; i ++ ) { cin...