链接:https://leetcode-cn.com/problems/k-diff-pairs-in-an-array/description/ Q: 给定一个整数数组和一个整数k, 你需要在数组里找到不同的k-diff数对。这里将k-diff数对定义为一个整数对 (i, j), 其中 i 和 j 都是数组中的数字,且两数之差的绝对值是k. 示例 1: 思路:k小于0 返回0
LeetCode 532. K-diff Pairs in an Array K-diff Pairs in an Array 题目描述: Given an array of integers and an integer k, you need to find the number of unique k-diff pairs in the array. Here a k-diff pair is defined as a......
532.K-diff Pairs in an Array 解题思路。 1、读题,数组中二数之差的绝对值为k。 2、只要遍历数组,每一个元素加上K值,还在原来的数组中,就找到一个解。 3、如果用数组遍历,会超时,通不过LeetCode 的测试,变…
如果k不等于0,遍历数组,将当前元素添加进set1,将当前元素加上k后再添加进set2,然后使用retainAll方法,将set1中不包含set2元素的元素剔除掉(也就是两set的交集),最后count等于set1中元素的个数。 publicintfindPairs4(int[] nums,intk){if(nums ==null|| nums.length ==0|| k <0) {return0; } Set...
Can you solve this real interview question? K-diff Pairs in an Array - Given an array of integers nums and an integer k, return the number of unique k-diff pairs in the array. A k-diff pair is an integer pair (nums[i], nums[j]), where the following are
Given an array of integersnumsand an integerk, returnthe number of unique k-diff pairs in the array. A k-diff pair is an integer pair(nums[i], nums[j]), where the following are true: 0 <= i, j < nums.length i != j
Given an array of integers and an integer k, you need to find the number of unique k-diff pairs in the array. Here a k-diff pair is defined as an integer pair (i, j), where i and j are both numbers in the array and their absolute difference is k. ...
https://leetcode-cn.com/problems/k-diff-pairs-in-an-array/ 2.思路 (1)思路是先排序之后做一次遍历,主要时间复杂度都在排序。 如果数组长度小于2或者k<0,直接返回0; 之后定义两个位置high和low,high代表较大的数,low代表较小的数。
532. K-diff Pairs in an Array C++ Java Python 535. Encode and Decode TinyURL 537. Complex Number Multiplication 538. Convert BST to Greater Tree 539. Minimum Time Difference 540. Single Element in a Sorted Array 541. Reverse String II 542. 01 Matrix 543. Diameter ...
对于一个整数数组nums,逆序对是一对满足0 <= i < j < nums.length且nums[i] > nums[j]的整数对[i, j]。 给你两个整数n和k,找出所有包含从1到n的数字,且恰好拥有k个逆序对的不同的数组的个数。由于答案可能很大,只需要返回对109+ 7取余的结果。