数组中的K-diff数对 - python 链接:https://leetcode-cn.com/problems/k-diff-pairs-in-an-array/description/ Q: 给定一个整数数组和一个整数 k, 你需要在数组里找到不同的 k-diff 数对。这里将 k-diff 数对定义为一个整数对 (i, j), 其中 i 和j 都是数组中的数字,且两数之差的绝对值是 k....
(题目:https://leetcode.com/problems/k-diff-pairs-in-an-array/#/description) 思路:把数组中的元素放到map中,key是数组中的值,value是该值在数组中出现的次数。构建好map之后,遍历数组,看看a[i]+k这个值在数组中是否存在。 答案:https://github.com/honpey/codebox/blob/master/leetcode/array/p532.cp...
Given an array of integers and an integer k, you need to find the number of unique k-diff pairs in the array. Here a k-diff pair is defined as an integer pair (i, j), where i and j are both numbers in the array and theirabsolute differenceis k. Example 1: Input: [3, 1, 4...
532.K-diff Pairs in an Array 解题思路。 1、读题,数组中二数之差的绝对值为k。 2、只要遍历数组,每一个元素加上K值,还在原来的数组中,就找到一个解。 3、如果用数组遍历,会超时,通不过LeetCode 的测试,变…
k, you need to find the number of unique k-diff pairs in the array. Here a k-diff pair is defined as an integer pair (i, j), where i and j are both numbers in the array and their absolute difference is k. ...
Explanation: There are two 2-diff pairs in the array, (1, 3) and (3, 5). Although we have two 1s in the input, we should only return the number of unique pairs. 1. 2. 3. 4. Example 2: Input:[1, 2, 3, 4, 5], k = 1 ...
Can you solve this real interview question? K-diff Pairs in an Array - Given an array of integers nums and an integer k, return the number of unique k-diff pairs in the array. A k-diff pair is an integer pair (nums[i], nums[j]), where the following are
Leetcode之K-diff Pairs in an Array 问题 /k-diff-pairs-in-an-array/description/) 思路分析:在这我们首先采用Hashmap来解决,因为hashmap的查找效率非常高,但是有一个问题:如果k=0的话,hashmap只会存一个。所以在... numbers in the array andtheir absolute difference isk.示例: Example1: Input: [3...
532. 数组中的K-diff数对 https://leetcode-cn.com/problems/k-diff-pairs-in-an-array/submissions/ 我的答案 可以点击到的最佳答案 所以他这里比我快的点就是他的collections.counter(nums) 用这个可以直接得到一个哈希表所以后面的调用就是count.items()...532. 数组中的K-diff数对 题目原文 给定一个...
532. 数组中的K-diff数对 https://leetcode-cn.com/problems/k-diff-pairs-in-an-array/submissions/ 我的答案 可以点击到的最佳答案 所以他这里比我快的点就是他的collections.counter(nums) 用这个可以直接得到一个哈希表所以后面的调用就是count.items()...532. 数组中的K-diff数对 题目原文 给定一个...