Can you solve this real interview question? Jump Game V - Given an array of integers arr and an integer d. In one step you can jump from index i to index: * i + x where: i + x < arr.length and 0 < x <= d. * i - x where: i - x >= 0 and 0 < x <= d. In
Can you solve this real interview question? Jump Game VI - You are given a 0-indexed integer array nums and an integer k. You are initially standing at index 0. In one move, you can jump at most k steps forward without going outside the boundaries of th
Notice that you can not jump outside of the array at any time. 题目来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/jump-game-v 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 --- 【难点分析】 某位置可访问的最多节点数与周围i-x ~ i+x的节点有关,容易想到...
LeetCode 55 题,即“跳跃游戏”(Jump Game),是一道经典的贪心算法问题。题目的要求是这样的。 给定一个非负整数数组nums,你最初位于数组的第一个索引处。数组中的每个元素代表你在该位置可以跳跃的最大长度。你的目标是判断你是否能够到达最后一个索引。 详细说明: 输入:一个数组nums,其中nums[i]表示从索引i处...
题目如下: Given an array of integersarrand an integerd. In one step you can jump from indexito index: i + xwhere:i + x < arr.lengthand0 < x <= d. i - xwhere:i - x >= 0and0 < x <= d. In addition, you can only jump from indexito indexjifarr[i] > arr[j]andarr[...
LeetCode 1340. Jump Game V (Java版; Hard) 题目描述 Given an array of integers arr and an integer d. In one step you can jump from index i to index: i + x where: i + x < arr.length and 0 < x <= d. i - x where: i - x >= 0 and 0 < x <= d. ...
数组中的每个元素代表你在该位置可以跳跃的最大长度。 判断你是否能够到达最后一个下标,如果可以,返回 true ;否则,返回 false。 示例1: 输入:nums = [2,3,1,1,4] 输出:true 解释:可以先跳 1 步,从下标 0 到达下标 1, 然后再从下标 1 跳 3 步到达最后一个下标。 示例2: 输入:nums = [3,2,1...
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LeetCode 55. Jump Game 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode Description Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that ...