然后问题就变成第一个位置也就是索引0是不是一个good index。 This is a dynamic programming question. Usually, solving and fully understanding a dynamic programming problem is a 4 step process: Start with the recursive backtracking solution (从递归回溯法入手) Optimize by using a memoization(记忆) ta...
inspired by the discussion in leetcode andhttp://tech-wonderland.net/blog/leetcode-jump-game-ii.html the keypoint of solving the problem by greedy approach is that we should keep the current maxium reachable distance, the next maxium reachable distance and also the steps needed to do it. w...
LeetCode 45. Jump Game II(Hard) 查阅更多的题解,请点击 Problem 45. Jump Game II(Hard) Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump......
LeetCode45. Jump Game II(C++) Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps. ...
Can you solve this real interview question? Jump Game III - Given an array of non-negative integers arr, you are initially positioned at start index of the array. When you are at index i, you can jump to i + arr[i] or i - arr[i], check if you can reach a
Problem: https://leetcode.com/problems/jump-game-ii/description/ Description: Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. ...
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leetcode / solution / 0000-0099 / 0045.Jump Game II / README_EN.md README_EN.md 2.78 KB 一键复制 编辑 原始数据 按行查看 历史 ylb 提交于 4年前 . feat: add solutions to lc problem: No.0045. Jump Game II 45. Jump Game II Description Solutions Python3 Java...
Leetcode - Jump Game Screenshot from 2016-02-17 23:10:39.png My code: publicclassSolution{publicbooleancanJump(int[]nums){if(nums==null)returnfalse;if(nums.length==0)returnfalse;if(nums.length==1)returntrue;boolean[]canJump=newboolean[nums.length];canJump[nums.length-1]=true;for(inti...
CodeTestcase Test Result Test Result 1340. Jump Game V Hard Topics Companies Hint Given an array of integers arr and an integer d. In one step you can jump from index i to index:i + x where: i + x < arr.length and 0 < x <= d....