http://www.lintcode.com/en/problem/jump-game/ 【题目解析】 我们需要知道能不能移动到最后一个元素位置。 采用贪心法即可,譬如上面的[2, 3, 1, 1, 4],因为初始第一个位置为2,我们先跳1步,剩下1步了,到第二个元素位置,也就是3这个地方,因为3比1大,所以我们可以向后面跳跃3步,直接就到4了。 根...
int jump_times = 0; while (now_step < last_index) { ++jump_times; int max_dis = 0; int jump_dis = nums[now_step]; if (now_step + nums[now_step] >= last_index)return jump_times; int next_step = 0; int mark_i; for (int i = 1; i <= jump_dis; ++i) { if ((now...
1.贪心算法中,作出的每步贪心决策都无法改变,因为贪心策略是由上一步的最优解推导下一步的最优解,而上一步之前的最优解则不作保留2.由(1)中的介绍,可以知道贪
Removes the last element in thevector, effectively reducing the containersizeby one ATTENTION: pop_back() just directly delete the last one so we needn't put things in () 46. Permutations Medium 220366FavoriteShare Given a collection of distinct integers, return all possible permutations. Example...
In the course of jumping, the player will visit the chessmen in the path, but everyone must jumps from one chessman to another absolutely bigger (you can assume start-point is a minimum and end-point is a maximum.). And all players cannot go backwards. One jumping can go from a ...
[translate] a但是,这也有缺点 But, this also vicious [translate] aHugh est un non-tout les larmes aux flus de la langue 休est联合国非招徕les larmes辅助flus de la langue [translate] atake at least 5 jump shots during the game 作为至少5个跳投在比赛期间 [translate] 英语...
solution / 0000-0099 / 0045.Jump Game II / README_EN.md README_EN.md2.78 KB 一键复制编辑原始数据按行查看历史 ylb提交于4年前.feat: add solutions to lc problem: No.0045. Jump Game II 45. Jump Game II 中文文档 Description Given an array of non-negative integersnums, you are init...
Would the spacebar work well on game using an external keyboard? Try this troubleshooting step for the built in keyboard and when done, test the game again using the built in keyboard. Perform a static discharge/power cycle - Remove all cables connected to the ...
The Trick of the Day part of the app is what I use most of all, as it gets me pick up my jump rope everyday and practice to get at least one of the tricks that day. I also love how you can slow down every video, mirror them and even get the app to create a combination for...
poses difficulties. Additionally, predicting which services will gain traction in the near term is highly challenging, and investing in technology dead ends is a risk no one can afford. Moreover, it is cost-prohibitive to deploy siloed platforms for each individual service at the edge, furthe...