常见的JSON库有org.json.JSONObject、com.alibaba.fastjson.JSONObject等。 检查JSON字符串是否有效:确保你传递给toJSONString方法的JSONObject对象不是空的,并且包含有效的JSON数据。如果JSON数据无效,例如缺少引号、缺少逗号等,将无法正常转换为JSON字符串,导致错误发生。 检查JSON对象是否包含非法字符:如果JSON对象的键...
jsonUser = JSONObject.toJSONString(user, SerializerFeature.PrettyFormat); System.out.println("情况一:\n" + jsonUser); /** * 情况二:包含值为null的属性 */ jsonUser = JSONObject.toJSONString(user, SerializerFeature.PrettyFormat, SerializerFeature.WriteMapNullValue); System.out.println("情况二:\n...
Stirng数据放入map中,再取出来是一个object,转换成String后,使用jsonObject.parseObject(),转换报了异常:com.alibaba.fastjson.JSONException: syntax error, expect {, actual string, pos 83, line 1, 解决方案:使用object.toString();来转换成String,不要使用JSONObject.toJSONString();Object parse = JSONObject...
"Alice");jsonObject.put("age",30);jsonObject.put("interests",newJSONArray(Arrays.asList("reading","traveling")));// 使用toString()StringtoStringOutput=jsonObject.toString();System.out.println("toString() Output:
1.MyJsonUtils.toJsonString 【toJsonString方法是自己定义的,详细如下】 public static String toJsonString(Object obj){ String jsonStr = null; try { jsonStr = mapper.wr
Tag Archives:json_object_to_json_string A simple and complete json parser Posted onAugust 19, 2010 Reply This parser makes use of all the functions which reads the value of a json object. This parser is complete in all respects. You can make use of the functions to create parser for you...
at com.alibaba.fastjson.JSON.toJSONString(JSON.java:421) at com.alibaba.fastjson.JSON.toJSONString(JSON.java:391) at me.huha.api.natives.NativeApis.supportNative(NativeApis.java:130) at me.huha.testController.GateWayController.support(GateWayController.java:36) ...
JsonObject.ConvertToJsonContext Constructors Fields CancellationToken Cmdlet CompressOutput EnumsAsStrings MaxDepth StringEscapeHandling Language MatchInfo MatchInfoContext MeasureCommandCommand MeasureInfo MeasureObjectCommand MemberDefinition ModuleCmdletBase
JsonObject.ConvertToJsonContext Constructors Fields CancellationToken Cmdlet CompressOutput EnumsAsStrings MaxDepth StringEscapeHandling Language MatchInfo MatchInfoContext MeasureCommandCommand MeasureInfo MeasureObjectCommand MemberDefinition ModuleCmdletBase
您好,我用最新的FastJson1.2.49的时候发现JSON.toJSONString(Object object)方法不可用,试了一下其他的几个toJsonString方法也不可应,追踪到源码中发现SerializeConfig这个类没有加载好,发现serializer整个包下面的所有的.class文件都打不开,提示invalid LOC header(ba