我们可以使用ObjectMapper类的readValue方法将JSON字符串转换为一个List<Student>对象数组。下面是完整的代码示例: importcom.fasterxml.jackson.core.type.TypeReference;importcom.fasterxml.jackson.databind.ObjectMapper;importjava.util.List;publicclassJsonToListExample{publicstaticvoidmain(String[]args){StringjsonString=...
public class HwInstance {private String fault;private String id;@JsonProperty("OS-EXT-STS:task_state")private String state;@JsonProperty("cpu_options")private Object options;} 转List 方法一：@Autowiredprivate ObjectMapper objectMapper;String json = "";JSONObject jsonObject = JSON.parseObject(json)...
然后,我们可以编写代码来将JSON字符串转换为List: importcom.fasterxml.jackson.databind.ObjectMapper;importjava.io.IOException;importjava.util.List;publicclassJsonToListConverter{publicstaticList<String>jsonStringToList(StringjsonString)throwsIOException{ObjectMapperobjectMapper=newObjectMapper();returnobjectMapper.readV...
2.2json字符串转成JsonArrayToList[],代码实现比较简单 packagecom.cppba.jackson;importcom.fasterxml.jackson.annotation.JsonProperty;importcom.fasterxml.jackson.databind.ObjectMapper;importjava.io.IOException;importjava.util.List;publicclassStringToObject{publicstaticObjectMapperobjectMapper=newObjectMapper();publicst...
configList.add(newItem("4","100")); String json=JSON.toJSONString(configList); System.out.println(json); List<Item> configList2 = JSON.parseArray(json,Item.class);for(Item item : configList2) { System.out.println(GsonUtils.toJson(item)); ...
//第一种方式List<Map<String,String>> listObjectFir=(List<Map<String,String>>)JSONArray.parse(strArr);System.out.println("利用JSONArray中的parse方法来解析json数组字符串");for(Map<String,String> mapList : listObjectFir){for(Map.Entryentry : mapList.entrySet()){System.out.println( entry....
jsonString转List (Fastjson) <?>Domain
1.后台接收json数组转成封装实体类的List package no.integrasco.ingentia.news.qaedition; public class Person { private String name; private int age; public String getName() { return name; } public void setName(String name) { this.name = name; ...
JSON类型的String转成ListString //后端调⽤接⼝ List<String> directives = new ArrayList<>();while (matcher.find()) { directives.add(matcher.group(1));LOGGER.info("处理标签：{}", matcher.group(1));} JSONObject jsonObject = new JSONObject();Map map2=new HashMap();//将List<String>...
String jsonArray = Files.readString(filePath); 我们将读取JSON内容转换为Person对象的List。 @Data @NoArgsConstructor @AllArgsConstructor class Person { long id; String name; int age; } 1.使用FastJson FastJson 是阿里巴巴的开源JSON解析库,它可以解析 JSON 格式的字符串,支持将 Java Bean 序列化为 JSON...