Count number of negative values in array# 需求: Write a function that takes an array of numbers as argument Return the number of negative values in the array 我的提交 functionmyFunction(a){varcount=0;for(vari=0;i<a.length;i++){if(a[i]<0){count++;}}returncount;} 作者答案 functionm...
Counting occurrencesThe reduce method can count occurrences of values in an array. main.js const fruits = ['apple', 'banana', 'apple', 'orange', 'banana', 'apple']; const count = fruits.reduce((acc, fruit) => { acc[fruit] = (acc[fruit] || 0) + 1; return acc; }, {}); ...
/** * @param { array } arr * @param {*} value */export function countOccurrences(arr, value) { return arr.reduce((a, v) => v === value ? a + 1 : a + 0, 0);}加法函数(精度丢失问题)/** * @param { number } arg1 * @param { number } arg2 */export function add(arg1...
11. `countOccurrences`:检测数值出现次数 constcountOccurrences= (arr, val) => arr.reduce((a, v) =>(v === val ? a +1: a),0);countOccurrences([1,1,2,1,2,3],1);// 3 12. `deepFlatten`:递归扁平化数组 constdeepFlatten= arr => [].concat(...arr.map(v=>(Array.isArray(v)...
countOccurrences计算数组中值的出现次数。使用Array.reduce()在每次遇到数组中的特定值时递增计数器。const countOccurrences = (arr, value) => arr.reduce((a, v) => v === value ? a + 1 : a + 0, 0); // countOccurrences([1,1,2,1,2,3], 1) -> 3...
/** * @param { array } arr * @param {*} value */ export function countOccurrences(arr, value) { return arr.reduce((a, v) => v === value ? a + 1 : a + 0, 0); } 加法函数(精度丢失问题) /** * @param { number } arg1 * @param { number } arg2 */ export function...
Array 数组最大值 Math.max()和扩展操作符... const arrayMax = arr => Math.max(...arr) 数组中去除假值 const compact = arr => arr.filter(Boolean) 统计某项出现的次数 const countOccurrences = (arr, value) => { return arr.reduce((a,v) =>{ ...
return Array.from( { length: Math.ceil(arr.length / size), }, (v, i) => arr.slice(i * size, i * size + size) ); } 检查数组中某元素出现的次数 function countOccurrences(arr, value) { return arr.reduce((a, v) => (v === value ? a + 1 : a + 0), 0); ...
JavaScript程序分析题 js编程题目,1.计算给定数组arr中所有元素的总和(数组中的元素均为Number类型)1functionsum(arr){2varsum=0;3for(vari=arr.length-1;i>=0;i--){4sum+=arr[i];5}6returnsum;7}8sum([1,2,3,4
function findAllOccurrences(arr, target) { var ans = [] for(let index in arr) { if(arr[index] == target) ans.push(index) } return ans } 1. 2. 3. 4. 5. 6. 7. 8. View Code 避免全局变量 题目描述 给定的 js 代码中存在全局变量,请修复 ...